Answer:
In 1 second he runs 6.0 meters.
Step-by-step explanation:
The question asks "how far does he run in one second?" The answer is a distance, not a time, so if it needs to be rounded, it is to the nearest tenth of a meter.
Divide the distance by the time:
(414.2 m)/(68.7 sec) = 6.029 m/sec
In 1 second he runs 6.0 meters.
Answer:
y = -x/4 + 7/2
Step-by-step explanation:
Find the slope
( -2 , 4) ( 6 , 2)
m = (y2 - y1)/(x2 - x1)
x1 = -2
y1 = 4
x2 = 6
y2 = 2
m = ( 2 - 4)/( 6 -(-2)
m = ( 2 -4)/(6 +2)
= -2/8
= -1/4
Using point slope form equation
y - y1 = m( x - x1)
Using the second point
( 6 , 2)
x1= 6
y1=2
m = -1/4
y - 2 = -1/4(x - 6)
y - 2 = -(x - 6)/4
Open the bracket with -
y - 2 = (-x + 6)/4
y = ( -x + 6)/4 + 2
LCM = 4
y =( -x + 6 + 8)/4
y = (-x + 14)/4
Rearrange using slope intercept form
y = mx + c.
y = -x/4 + 14/4
We can break 14/4 by dividing by 2
y = -x/4 + 7/2
Answer: The width of the field = 160 feet
Step-by-step explanation:
We are given that , A field is 
yards wide.
That means , The width of the field = yards
Since , the fraction is in mixed for , so first we convert this into improper fraction.
Therefore , the width of the field = 
yards
Since 1 yard = 3 feet.
⇒ the width of the field = 
feet
Therefore , the width of the field = 160 feet
Answer:
x² = y
Step-by-step explanation:
x² = y fit one input to one output property of function
The correct answer isw=1/2x
