Answer:
32°
Step-by-step explanation:
Given:
∠DMQ = 58º
In this circle, the radius is DM. Since AD is tangent to the circle M, at point D, and the angle between a tangent and a radius is 90°
Therefore, ∠MDQ = 90°
The total angle in a triangle is 180°. Since we have the values of ∠MDQ and ∠DMQ, ∠DQM will be calculated as:
180 = ∠DMQ + ∠MDQ + ∠DQM
Solving for ∠DQM, we have:
∠DQM = 180 - ∠DMQ - ∠MDQ
∠DQM = 180 - 90 - 58
∠DQM = 32°
The measure of ∠DQM is 32°
Answer:
Step-by-step explanation:
Here, we add up two polynomials shown.
The polynomials are:
In order to add up the 2 polynomials shown, we have to see the "like terms" and add them up.
We add up the "" terms and the constant (number) terms. There is one term with "m", so we leave it like that. Let's add up. Shown below:\
This is the sum of the 2 polynomials shown:
Step-by-step explanation:
<h3>Solved in the attachment!! </h3><h3>Hope it helps you!! </h3>