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ra1l [238]
2 years ago
6

Complete the table of values for y = 6 - 2x

Mathematics
1 answer:
Tpy6a [65]2 years ago
5 0

Step-by-step explanation:

a) substitute x values:

6-2(0) = 6

6-2(1) = 4

6-2(2) = 2

6-2(3) = 0

6-2(4) = -2

6-2(5) = -4

b) rewrite equation as y=-2x+6.

this shows a negative slope with a y-intercept of 6.

c) 3=6-2x

  -6 -6

-3 = -2x

divide both sided by 2

-3/-2 = x

3/2=x

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Question Help Suppose that the lifetimes of light bulbs are approximately normally​ distributed, with a mean of 5656 hours and a
koban [17]

Answer:

a)3.438% of the light bulbs will last more than 6262 hours.

b)11.31% of the light bulbs will last 5252 hours or less.

c) 23.655% of the light bulbs are going to last between 5858 and 6262 hours.

d) 0.12% of the light bulbs will last 4646 hours or less.

Step-by-step explanation:

Normally distributed problems can be solved by the z-score formula:

On a normaly distributed set with mean \mu and standard deviation \sigma, the z-score of a value X is given by:

Z = \frac{X - \mu}{\sigma}

After we find the value of Z, we look into the z-score table and find the equivalent p-value of this score. This is the probability that a score will be LOWER than the value of X.

In this problem, we have that:

The lifetimes of light bulbs are approximately normally​ distributed, with a mean of 5656 hours and a standard deviation of 333.3 hours.

So \mu = 5656, \sigma = 333.3

(a) What proportion of light bulbs will last more than 6262 ​hours?

The pvalue of the z-score of X = 6262 is the proportion of light bulbs that will last less than 6262. Subtracting 100% by this value, we find the proportion of light bulbs that will last more than 6262 hours.

Z = \frac{X - \mu}{\sigma}

Z = \frac{6262 - 5656}{333.3}

Z = 1.82

Z = 1.81 has a pvalue of .96562. This means that 96.562% of the light bulbs are going to last less than 6262 hours. So

P = 100% - 96.562% = 3.438% of the light bulbs will last more than 6262 hours.

​(b) What proportion of light bulbs will last 5252 hours or​ less?

This is the pvalue of the zscore of X = 5252

Z = \frac{X - \mu}{\sigma}

Z = \frac{5252- 5656}{333.3}

Z = -1.21

Z = -1.21 has a pvalue of .1131. This means that 11.31% of the light bulbs will last 5252 hours or less.

(c) What proportion of light bulbs will last between 5858 and 6262 ​hours?

This is the pvalue of the zscore of X = 6262 subtracted by the pvalue of the zscore X = 5858

For X = 6262, we have that Z = 1.81 with a pvalue of .96562.

For X = 5858

Z = \frac{X - \mu}{\sigma}

Z = \frac{5858- 5656}{333.3}

Z = 0.61

Z = 0.61 has a pvalue of .72907.

So, the proportion of light bulbs that will last between 5858 and 6262 hours is

P = .96562 - .72907 = .23655

23.655% of the light bulbs are going to last between 5858 and 6262 hours.

​(d) What is the probability that a randomly selected light bulb lasts less than 4646 ​hours?

This is the pvalue of the zscore of X = 4646

Z = \frac{X - \mu}{\sigma}

Z = \frac{4646- 5656}{333.3}

Z = -3.03

Z = -3.03 has a pvalue of .0012. This means that 0.12% of the light bulbs will last 4646 hours or less.

5 0
3 years ago
Hi, could someone help me answer this please? Thanks!
rusak2 [61]

13,986

Step-by-step explanation:

Juss used a calculator, the rest guess

8 0
3 years ago
Write an equivalent ratio for 7:8 with 40 as one of the terms.
kvv77 [185]

Answer:

Step-by-step explanation:

Five equivalent ratios:

7:8  = 14:16

      = 21:24

      = 70:80

      = 49:56

      = 35:40

8 0
2 years ago
What is the coefficient of the term 7y in the expression 9 + 7y
kakasveta [241]

Answer:

7 is the coefficient of 7y

Step-by-step explanation:

explanation in the text book pls refer TB

6 0
2 years ago
For a certain​ candy, 15​% of the pieces are​ yellow, 5​% are​ red, 20​% are​ blue, 20​% are​ green, and the rest are brown. ​a)
LuckyWell [14K]
P(Brown) = 100 - 15 -5- 20 - 20 = 40%

P(yellow or blue) = 15 + 20 = 35%

P(not green) = 100 - 20 = 80%

P(striped) = 0%
3 0
3 years ago
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