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Vinil7 [7]
3 years ago
15

Find two numbers if their sum is 7.2 and their difference is 2.7

Mathematics
2 answers:
Klio2033 [76]3 years ago
8 0

Answer:

4.95 and 2.25

Step-by-step explanation:

x+y=7.2

x-y=2.7

Add equations

x+y + x-y= (2x-y+y)=2x

7.2+2.7=9.9

Therefore 2x=9.9 x=9.9/2=4.95

x=4.95

x+y=7.2

4.95+y=7.2

y=7.2-4.95=2.25

y=2.25

luda_lava [24]3 years ago
4 0

Answer:

4.95 and 2.25.

Step-by-step explanation: This is really long... (PLEASE TAKE NOTE THE INFO ISNT DIRECTLY WRITTEN BY ME).


Adding equations (1) and (2), we get

Therefore

x=4.95


Substituting value of x from (3) in (1), we get


y=2.25


From (3) and (4), the two numbers are 4.95 and 2.25.

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If your score on your next statistics test is converted to a z​ score, which of these z scores would you​ prefer: minus−​2.00, m
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Segment VY is a midsegment of trapezoid FEDC. Find x.
Morgarella [4.7K]

Answer:

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Step-by-step explanation:

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3x + 18 = \frac{1}{2} (x + 96) ← multiply both sides by 2 to clear the fraction

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Historical data indicates that only 20% of cable customers are willing to switch companies. If a binomial process is assumed, th
Natasha_Volkova [10]

Answer:

a. The probability is 0.735

b. The probability is 0.6296

c. The probability is 0

Step-by-step explanation:

If we assume a binomial process, the probability that x customer are willing to switch companies is:

P(x)=nCx*p^{x}*(1-p)^{n-x}

nCx is calculated as:

nCx=\frac{n!}{x!(n-x)!}

Where n are the 20 cable customers and p is the probability 0.2 that the cable customer are willing to switch companies.

Then, P(x) is:

P(x)=20Cx*0.2^{x}*(1-0.2)^{20-x}

The probability that between 2 and 5 (inclusive) customers are willing to switch companies is:

P(2≤x≤5) = P(2) + P(3) + P(4) + P(5)

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P(3)=20C3*0.2^{3}*(1-0.2)^{20-3}=0.2054

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P(x>16)=P(17)+P(18)+P(19)+P(20)

P(x>16)=0

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