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Contact [7]
4 years ago
15

Be sure to answer all parts. Dinitrogen difluoride, N2F2, is the only stable, simple inorganic molecule with an N=N bond. The co

mpound occurs in cis and trans forms. (a) Select which of the molecular shapes of N2F2 correspond to the cis and trans form of N2F2. I h5a II h5b III h5c cis-dinitrogen fluoride: I II III trans-dinitrogen fluoride: I II III (b) Predict the polarity, if any, of each form. cis = polar; trans = polar cis = polar; trans = nonpolar cis = nonpolar; trans = polar cis = nonpolar; trans = nonpolar

Chemistry
2 answers:
Marianna [84]4 years ago
8 0

Answer:

(a) The molecular shapes of cis and Trans forms of N2F2 are-

b) There is EN difference between N atom and F atom. Hence the molecule will have a bond dipole.

In Cis form two fluorine atoms are on the same side of N N bond. Hence, bond moment in N2F2 cis form) do not cancel each other. Thus the cis form is polar.

In the trans form two fluorine atoms are on the opposite side of N-N bond. Bond moment of NF cancels each other.

Thus: trans N2F2 is non polar molecule.

ASHA 777 [7]4 years ago
3 0

(a) The molecular shapes of cis and Trans forms of N2F2 are-


b) There is EN difference between N atom and F atom. Hence the molecule will have a bond dipole.

In Cis form two fluorine atoms are on the same side of N N bond. Hence, bond moment in N2F2 cis form) do not cancel each other. Thus the cis form is polar.

In the trans form two fluorine atoms are on the opposite side of N-N bond. Bond moment of NF cancels each other.

Thus: trans N2F2 is non polar molecule.

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How many grams of h2o are needed to produce 45g of NO
schepotkina [342]

We need (i) the stoichiometric equation, and (ii) the equivalent mass of dihydrogen.
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Whatever this molar quantity is, it is clear from the stoichiometry of the reaction that 3/2 equiv of dihydrogen gas were required. How much dinitrogen gas was required?
4 0
3 years ago
Pls help me will mark brainliest, chemistry equilibrium!!!
Sergeeva-Olga [200]

Answer:

See attached => LeChatelier's Principle

Explanation:

LeChatelier's Principle => If a stress is applied to a chemical reaction, the reaction chemistry will shift away from the applied stress and establish a new equilibrium having new concentration values different from the original concentration values.

There are three (3) principle stress factors that will cause disturb a chemical reaction and cause it to shift to establish a new equilibrium. These are ...

=> concentration effects,

=> temperature effects, and

=> pressure-volume effects.

The attached notes explain in general terms how to evaluate a chemical reaction under an applied stress factor and determine direction of shift to establish a new equilibrium stability. Compare and apply to the worksheet problems.

_______

Answers to worksheet (compare to attached notes)

1a. => increasing wt to product side => tilts right => shifts left

1b. => removing wt from reactant side => tilts right => shifts left,

1c. => increasing wt to product side => tilts right => shifts left

2a. => tilts left (excess wt from Hg), shifts right,

2b. => Increase pressure shifts toward lower molar gas volume side (right) Note: apply only to gas phase substances, Hg is in liquid phase.

3a. exothermic rxn => cooling => tilts left, rxn shifts right

3b. endothermic rxn => cooling => tilts right, rxn shifts left

3c. exothermic rxn => cooling => tilts left, rxn shifts right

_____________

don't forget => brainliest :-)

3 0
3 years ago
using the following thermochemical equation, determine the amount of heat produced from the combustion of 24.3 g benzene (c6h6).
aliya0001 [1]

the amount of heat produced from the combustion of 24.3 g benzene (c6h6) is ΔH = -976.5 kJ

There are two moles of benzene involved in the process (C6H6). Since the heat of this reaction is -6278 kJ, the burning of 2 moles of benzene will result in a heat loss of 6278 kJ. This reaction is exothermic.

Enthalpy, or the value of H, is a unit of measurement for heat that relies on the amount of matter present (number of moles).

Thus, 24.3 g of benzene contains:

n = mass/molar mass, where n = 24.3/78.11, and n = 0.311 moles.

2 moles = 6278 kJ

0.311 moles =x

By the straightforward direct three rule:

2x = -1953.08 x = -976.5 kJ

Learn more about combustion here-

brainly.com/question/15117038

#SPJ4

4 0
1 year ago
HELP ME PLEASE ILL MARK U THE BRAINLIEST
ElenaW [278]

Answer:

pentene-alkanes-C5H10

octane-alkanes-C 8H 18

butene-alkene-c4h8

decane-alkane-c10h22

6 0
3 years ago
23.5 L of h2 is stored at a pressure of 58.7 Kpa what volume would the gas take up at stp
stepan [7]

Answer:-  13.6 L

Solution:- Volume of hydrogen gas at 58.7 Kpa is given as 23.5 L. It asks to calculate the volume of hydrogen gas at STP that is standard temperature and pressure. Since the problem does not talk about the original temperature so we would assume the constant temperature. So, it is Boyle's law.

Standard pressure is 1 atm that is 101.325 Kpa.

Boyle's law equation is:

P_1V_1=P_2V_2

From given information:-

P_1 = 58.7 Kpa

V_1 = 23.5 L

P_2 = 101.325 Kpa

V_2 = ?

Let's plug in the values and solve it for final volume.

58.7Kpa*23.5L=101.325Kpa*V_2

On rearranging the equation for V_2

V_2=\frac{58.7Kpa*23.5L}{101.325Kpa}

V_2 = 13.6 L

So, the volume of hydrogen gas at STP for the given information is 13.6 L.

3 0
3 years ago
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