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NeTakaya
4 years ago
9

A large sample of solid calcium is crushed into smaller pieces for testing. Which two physical properties are the same for both

the large sample and one of the smaller pieces?
Chemistry
1 answer:
jarptica [38.1K]4 years ago
5 0
Lets go over what our properties are

-Mass is a measure of the amount of matter available. 
<span>
-Density is the ratio of mass to volume. Density is determined to be a physical object</span>

<span>-Volume is the amount of space occupied by the object. </span>

<span>-Solubility is the amount of a substance required to form a saturated solution with a specific amount of solvent at a specified temperature. 
</span>
-Mass is the same size and weight of an object for the most part which cannot be the same for a bigger or smaller object. Which means density cannot either since density has a direct correlation with mass. Volume is usually the size occupied at the current time. This means it cannot be the same for a large and small object. Note that! Then we have solubility which is the amount required or needed but since you are just crushing the solid it would wind up still being the same amount.

-With this all put together we can say your answer is probably Solubility and Desnity.
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I don’t need brainliest but please just mark thanks to this answer that would help me a lot, have a nice day :)
7 0
3 years ago
Given 6193 mL of a gas at 62.3 °C. What is its volume at 38.1 °C?
Luden [163]

Answer:

5746.0 mL.

Explanation:

We can use the general law of ideal gas:<em> PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have two different values of V and T:

<em>V₁T₂ = V₂T₁</em>

<em></em>

V₁ = 6193.0 mL, T₁ = 62.3°C + 273 = 335.3 K.

V₂ = ??? mL, T₂ = 38.1°C + 273 = 311.1 K.

<em>∴ V₂ = V₁T₂/T₁ </em>= (6193.0 mL)(311.1 K)/(335.3 K) = <em>5746.0 mL.</em>

5 0
3 years ago
what will be the new volume of a 250mL sample of gas at 300 k and 1 atm if heated to 350 k at 1 atm law use:
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Answer:

292 mL

Step-by-step explanation:

The pressure is constant.

The only variables are volume and temperature, so we can use <em>Charles’ Law.</em>

V₁/T₁ = V₂/T₂     Multiply each side by T₂

V₂ = V₁ × T₂/T₁

V₁ = 250 mL; T₁ = 300 K  

V₂ = ?;           T₂ =  350 K

V₂ = 250 × 350/300

V₂ = 292 mL

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