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NeTakaya
3 years ago
9

A large sample of solid calcium is crushed into smaller pieces for testing. Which two physical properties are the same for both

the large sample and one of the smaller pieces?
Chemistry
1 answer:
jarptica [38.1K]3 years ago
5 0
Lets go over what our properties are

-Mass is a measure of the amount of matter available. 
<span>
-Density is the ratio of mass to volume. Density is determined to be a physical object</span>

<span>-Volume is the amount of space occupied by the object. </span>

<span>-Solubility is the amount of a substance required to form a saturated solution with a specific amount of solvent at a specified temperature. 
</span>
-Mass is the same size and weight of an object for the most part which cannot be the same for a bigger or smaller object. Which means density cannot either since density has a direct correlation with mass. Volume is usually the size occupied at the current time. This means it cannot be the same for a large and small object. Note that! Then we have solubility which is the amount required or needed but since you are just crushing the solid it would wind up still being the same amount.

-With this all put together we can say your answer is probably Solubility and Desnity.
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Determine the empirical formula for a compound that contains 15.8% carbon and 84.2% sulfer
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What dose it mean to say that mass is conserved during a physical change?
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A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. Calculate the pressure when the volume is 1.41 L and the
Vlad1618 [11]

A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

<h3>What is Combined Gas Law ?</h3>

This law combined the three gas laws that is (i) Charle's Law (ii) Gay-Lussac's Law and (iii) Boyle's law.

It is expressed as

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where,

P₁ = first pressure

P₂ = second pressure

V₁ = first volume

V₂ = second volume

T₁ = first temperature

T₂ = second temperature

Now put the values in above expression we get

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

\frac{1.02\ atm \times 2.30\ L}{281\ K} = \frac{P_2 \times 1.41\ L}{298\ K}

P_{2} = \frac{1.02\ atm \times 2.30\ L \times 298\ K}{281\ K \times 1.41\ L}

P₂ = 1.76 atm

Thus from the above conclusion we can say that A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

Learn more about the Combined gas Law here: brainly.com/question/13538773

#SPJ4

4 0
2 years ago
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