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djyliett [7]
3 years ago
5

Rewrite the formula for the circumference of a circle, C = 271, in terms of its diameter, d. Use pi for at in your response. d =

​
Mathematics
1 answer:
leva [86]3 years ago
7 0

Answer:

The circumference is 2*pi*r

But in terms of diameter the circumference is pi*d

Because the diameter is equal to 2*radius

Follow and like if this was useful

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Henry knows that the area of a rectangle is 30 square inches. The perimeter is 22 inches. If the length is 1 inch longer than th
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The length is 6 inches and the width is 5 inches
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Can someone please help me
erica [24]

Answer:

A=120

B=165

C=240

Step-by-step explanation:

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2 years ago
A projector was sold after allowing 10% discount on the marked price and levying 13% VAT .If the selling price of the projector
Tom [10]

The marked price of the projector is $50,000.

<h3>What is the marked price?</h3>

The price of the projector after the discount can be represented with:

(100 - 10%)x - 90%x = 0.90x

Where x is the marked price

The price of the projector after the VAT is : (1.13) x 0.90x = 1.02x

Difference in price = 1.02x - 0.90x = 5850

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x = 5850 / 0.12

x = $50,000

To learn more about how to calculate discounts, please check: brainly.com/question/26061308

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8 0
2 years ago
(-7x+8y-2z)+(-9x-y+6z)​
Svetach [21]

Answer: the answer is -16x+7y+4z

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Let X1, X2 and X3 be three independent random variables that are uniformly distributed between 50 and 100.
sergejj [24]

Answer:

a) the probability that the minimum of the three is between 75 and 90 is 0.00072

b) the probability that the second smallest of the three is between 75 and 90 is 0.396

Step-by-step explanation:

Given that;

fx(x) = { 1/5 ; 50 < x < 100

              0, otherwise}

Fx(x) = { x-50 / 50 ; 50 < x < 100

                          1 ;   x > 100

a)

n = 3

F(1) (x) = nf(x) ( 1-F(x)^n-1

= 3 × 1/50 ( 1 - ((x-50)/50)²

= 3/50 (( 100 - x)/50)²

=3/50³ ( 100 - x)²

Therefore P ( 75 < (x) < 90) =  ⁹⁰∫₇₅ 3/50³ ( 100 - x)² dx

= 3/50³ [ -2 (100 - x ]₇₅⁹⁰

= (3 ( -20 + 50)) / 50₃

= 9 / 12500 = 0.00072

b)

f(k) (x) = nf(x)  ( ⁿ⁻¹_k₋ ₁) ( F(x) )^k-1 ; ( 1 - F(x) )^n-k

Now for n = 3, k = 2

f(2) (x) = 3f(x) × 2 × (x-50 / 50) ( 1 - (x-50 / 50))

= 6 × 1/50 × ( x-50 / 50) ( 100-x / 50)

= 6/50³ ( 150x - x² - 5000 )

therefore

P( 75 < x2 < 90 ) = 6/50³ ⁹⁰∫₇₅ ( 150x - x² - 5000 ) dx

= 99 / 250 = 0.396

3 0
3 years ago
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