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djyliett [7]
3 years ago
5

Rewrite the formula for the circumference of a circle, C = 271, in terms of its diameter, d. Use pi for at in your response. d =

​
Mathematics
1 answer:
leva [86]3 years ago
7 0

Answer:

The circumference is 2*pi*r

But in terms of diameter the circumference is pi*d

Because the diameter is equal to 2*radius

Follow and like if this was useful

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HELP ME WITH THIS QUESTION PLEASE
lara [203]

Answer:

  • 0.79

Step-by-step explanation:

all you really need to do is multiply your decimal (15.8) by your percent (5) so, you problem would look like 15.8(.05) (note it is .<em>0</em>5 because there need to be 2 decimal places) so, your answer is .79

6 0
3 years ago
PLEASE HELPPP (NO LINKS) (NO LINKS) (NO LINKS)
rosijanka [135]

Answer:

  • B, B, C

Step-by-step explanation:

1.

Shirts cost $20 each and ties cost $12 each.

<u>Expression for the cost:</u>

  • 20s + 12t

Correct choice is B

2.

<u>An expression that represents 40% of a number is:</u>

  • 40*n/100 = 0.4n

Correct choice is B. False

3.

t = -2, x = 3 and z = 5

  • 4z + 3x − t =
  • 4*5 + 3*3 - (-2) =
  • 20 + 9 + 2 =
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Correct choice is C. 31

3 0
3 years ago
Read 2 more answers
How do you divide scientific notation problems like this: 0.00053 ÷ 29?
Shtirlitz [24]
You got to remember
\frac{x^m}{x^n}=x^{m+n}

first write them in scienfitic notation
0.00053=5.3*10^{-4}
29=2.9*10^1


so
\frac{0.00053}{29}=
\frac{(5.3)(10^{-4})}{(2.9)(10^1)}=
(\frac{5.3}{2.9})(\frac{10^{-4}}{10^1}=
(1.8275862068965517241379310344828)(10^{-4-1})=
(1.8275862068965517241379310344828)(10^{-5})=
1.8275862068965517241379310344828*10^{-5}

that's the answer
5 0
3 years ago
I will give you brainliest!
Bingel [31]

Answer:

110

Step-by-step explanation:

i think if its wrong im sorry

6 0
3 years ago
The lengths of two sides of a triangle are shown below:
oksano4ka [1.4K]

<u>Part A</u>

<u />3x^2 -2x-1+9x+2x^2 -3=\boxed{5x^2 + 7x-4}

<u>Part B</u>

<u />(5x^3 +4x^2 - x-3)-(5x^2 + 7x-4)=\boxed{5x^3 - x^2 - 8x+1}

<u>Part C</u>

No, because although they provide examples for specific polynomials being closed under addition and subtraction, there is a loss of generality.

6 0
2 years ago
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