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victus00 [196]
3 years ago
12

Question 3 of 10

Mathematics
1 answer:
MrMuchimi3 years ago
6 0

Answer:

The point-slope form  of the line is:

y + 4 = 4(x+3)

Hence, option B is correct.

Step-by-step explanation:

We know the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

Given

The slope m = 4

From the graph, we can take the point (-3, -4)

So, in our case:

(x₁, y₁) = (-3, -4)

m = 4

now substituting m = 4 and (x₁, y₁) = (-3, -4) in the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

y - (-4) = 4(x - (-3))

y + 4 = 4(x+3)

Therefore, the point-slope form  of the line is:

y + 4 = 4(x+3)

Hence, option B is correct.

  • The graph of the line is also attached.

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Snow Crest is 11,508.21 feet higher than Mt. Wilson. Write and solve an equation to find the elevation of Mt. Wilson. Let x repr
Viefleur [7K]

Answer:

16642.1 feets

Step-by-step explanation:

Given :

Elevation of Mt. Wilson = x

If the elevation of snow crest = y

Snow crest = 11,508.21 feet higher than Mt. Wilson

Hence, y = 11,508.21 + x

The elevation of Mt. Wilson, x = y - 11,508.21  feets

From the table, elevation of Snow crest = 28,150.31 feets = y

Hence, The elevation of Mt. Wilson, x = y - 11,508.21  feets

x = 28,150.31 - 11,508.21

x = 16642.1 feets

5 0
3 years ago
1÷13×2+181÷29383÷2×2=​
elena55 [62]
0.16000617835

You do 1/13 first then multiple by 2, save that answer we use it later, then you do 181/29383 get that answer and divide that answer by 2 and then multiply by 2 and now you take the very first answer we got with the 1/13 * 2 and you add that to the answer you got from 181/29383 divided by 2 multiplied by 2 and that’s how I got my answer.
5 0
3 years ago
Read 2 more answers
Please I need help urgently​
mezya [45]

Answer:

Area = 5(x + 4y - 6).

Step-by-step explanation:

The area of the whole figure = area of rectangle + area of the triangle

= 10(2y - 3)  + 1/2 * 10 * x

= 20y - 30 + 5x

= 5(x + 4y - 6).

3 0
3 years ago
Please help!!!!! ASAP!!!
nika2105 [10]
That's just the distance between 2 points
the distance between (x1,y1) and (x2,y2) is
D= \sqrt{(x2-x1)^2+(y2-y1)^2}

we can find the distance between S and Q or P and R

S and Q is (0,0) and (a,b)

D= \sqrt{(a-0)^2+(b-0)^2}
D= \sqrt{a^2+b^2}

distance between P and R is between(0,b) and (a,0)
D= \sqrt{(a-0)^2+(0-b)^2}
D= \sqrt{(a)^2+(-b)^2}
D= \sqrt{a^2+b^2}

\sqrt{a^2+b^2} = \sqrt{a^2+b^2}
so the lengths of diagonals are congruent
7 0
4 years ago
If set D is not the empty set but is a subset of set E, then which of the following is true?
MrRa [10]
D∩E=D This is because since D is a subset of E then the elements they will have in common are the elements in D and D is not a null set
3 0
4 years ago
Read 2 more answers
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