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victus00 [196]
3 years ago
12

Question 3 of 10

Mathematics
1 answer:
MrMuchimi3 years ago
6 0

Answer:

The point-slope form  of the line is:

y + 4 = 4(x+3)

Hence, option B is correct.

Step-by-step explanation:

We know the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

Given

The slope m = 4

From the graph, we can take the point (-3, -4)

So, in our case:

(x₁, y₁) = (-3, -4)

m = 4

now substituting m = 4 and (x₁, y₁) = (-3, -4) in the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

y - (-4) = 4(x - (-3))

y + 4 = 4(x+3)

Therefore, the point-slope form  of the line is:

y + 4 = 4(x+3)

Hence, option B is correct.

  • The graph of the line is also attached.

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I already finished it but how do you know if it’s decreasing or increasing?
nexus9112 [7]

Answer:

If the slope is positive it is increasing if the slope is negative it is decreasing :)

Example:

Y=mX+b

If m is positive it is a positive slope

6 0
3 years ago
Read 2 more answers
If the standard deviation of a data set were originally 12, and if each value in
Zanzabum

Answer: 21

Step-by-step explanation:

Take 12 and multiply it by 1.75 (12x1.75) and you’ll get 21

6 0
2 years ago
Ayesha has a theory about two digit numbers that have a larger tens digit than ones digit. she says that reversing the digits an
stira [4]
<span>Ayesha's right.  There's a good trick for knowing if a number is a multiple of nine called "casting out nines."  We just add up the digits, then add up the digits of the sum, and so on.  If the result is nine the original number is a multiple of nine.  We can stop early if we recognize if a number along the way is or isn't a multiple of nine.  The same trick works with multiples of three; we have one if we end with 3, 6 or 9.

So </span>1284673 <span>has a sum of digits 31 whose sum of digits is 4, so this isn't a multiple of nine.  It will give a remainder of 4 when divided by 9; let's check.

</span>1284673 = 142741 \times 9 + 4 \quad\checkmark<span>

</span>Let's focus on remainders when we divide by nine. The digit summing works because 1 and 10 have the same remainder when divided by nine, namely 1.  So we see multiplying by 10 doesn't change the remainder.  So 100 \times a + 10 \times b + c has the same remainder as a+b+c.

When Ayesha reverses the digits she doesn't change the sum of the digits, so she doesn't change the remainder.  Since the two numbers have the same remainder, when we subtract them we'll get a number whose remainder is the difference, namely zero. That's why her method works.
<span>
It doesn't matter if the digits are larger or smaller or how many there are. We might want the first number bigger than the second so we get a positive difference, but even that doesn't matter; a negative difference will still be a multiple of nine. Let's pick a random number, reverse its digits, subtract, and check it's a multiple of nine:

</span>813219543092195 - 591290345912318 =  221929197179877 = 9 \times 24658799686653 \quad \checkmark

6 0
3 years ago
Read 2 more answers
Seventy percent of children who go to the doctor have fevers. Of those with fevers, 30% also have a rash. Of those without fever
Allisa [31]

Answer:

The probability that a child with a rash does not have a fever is 22%

Step-by-step explanation:

1. Probability of having fever:

P(fever)=0.70

2. Probability of not having fever:

P(not fever)=1-P(fever)\\P(not fever)=1-0.70\\P(not fever)=0.30

3. Probability of fave fevers and a rash:

P(fever and rash)=(0.70)(0.30)=0.21

4. Probability of having a rash but not a fever:

P(rash and not fever)=(0.30)(0.20)=0.60

5. Probability of having a rash:

P(rash)=P(rash and fever)+P(rash and no fever)\\P(rash)=0.21+0.06=0.27

6. Probability a child with a rash does not have a fever

P=\frac{P(rash and not fever)}{P(rash)} =\frac{0.06}{0.27} =0.22

22% of the child at the doctor's office with a rash does not have a fever.

5 0
3 years ago
The image of the point (-5,4) under a reflection across the Y-axis is (5,4). True or false
Vanyuwa [196]

The answer is true. A reflection is a translation over an axis

7 0
3 years ago
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