All categories

2 years ago

If 8^x=27, then what is 4^(2x-3)?

Mathematics

1 answer:

Leviafan [203]2 years ago

7 0

Answer:

Step-by-step exExplanation:

−

(

)

(

)

You might be interested in

20 POINTS If the perimeter of a triangle is 14.4. What is the area?

sweet-ann [11.9K]

Answer:

A = 9.9648

Step-by-step explanation:

if the triangle is equilateral =>

P = 3L => L = 14.4/3 = 4.8

A = L²√3/4

= (4.8)²√3/4

= 23.04√3/4

= 5.76×1.73

= 9.9648

7 0

3 years ago

3(2x+x)/6 > 1/3x+2 solve for x

tangare [24]

1)Find all the like terms=3x3x/6>1/3x+2

2)Multiply both sides by six=9x>2x+12

3)Move the variables to the left side and change the sign=9x-2x>12

4)Find the like terms=7x>12

5)Divide by sides by seven=x>12/7

6)Your answer is x>12/7

I hope this helps! :)

4 0

2 years ago

Graph the linear equation by plotting the x and y intercepts <br> x +4y -16 =0

ira [324]

Answer:

x intercept = 16

y intercept = 4

Step-by-step explanation:

For the x intercept...y = 0...where the equation would be...x + 4(0) = 16..hence giving us the x intercept as... x = 16

For the y intercept...x = 0...where if we substitute x = 0 into our equation...the equation would be....0 + 4y = 16..hence giving us..., 4y = 16...divide both sides by 4...y = 4

5 0

3 years ago

Which can be the first step in finding the equation of the line that passes through the points (5, -4) and (-1, 8) in slope-inte

abruzzese [7]

Answer:

y = -2x + 6

Step-by-step explanation:

Slope = (-4 - 8)/(5 + 1)

= -12/6

= -2

Equation

y - 8 = -2(x + 1)

y - 8 = -2x - 2

y = -2x + 6 <-----------slope-intercept form

7 0

2 years ago

Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an

Natasha_Volkova [10]

Answer:

The volume of the solid is 243 $\sqrt{2} \ \pi$

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0 ≤ ρ² ≤ 81

0 ≤ ρ ≤ 9

The intersection that takes place in the sphere and the cone is:

$x^2 +y^2 ( \sqrt{x^2 +y^2 })^2 = 81$

$2(x^2 + y^2) =81$

$x^2 +y^2 = \dfrac{81}{2}$

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

$z = \sqrt{x^2+y^2}$

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; $\dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}$

Thus, volume: $V = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4} \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho ^2 \ sin \phi \ d\rho \ d \theta \ d \phi$

$V = \int \limits^{\pi/2}_{\pi/4} \ sin \phi \ d \phi \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho ^2 d\rho$

$V = \bigg [-cos \phi \bigg]^{\pi/2}_{\pi/4} \bigg [\theta \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3} \bigg ]^{9}_{0}$

$V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]$

V = 243 $\sqrt{2} \ \pi$

4 0

2 years ago