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klemol [59]
3 years ago
14

Which expression is equivalent to 6 (3x + 4)? 9x + 10 9.C +4 18.2 + 4 18.2 + 24

Mathematics
1 answer:
vitfil [10]3 years ago
5 0
I think it’s 18.2+24
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PLEASE SOMEONE HELP ME
posledela
My name is Sarai to, lol
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3 years ago
Denise bought a T-shirt at the sale price of $24. The original cost of a T-shirt was $40. What percent represents the discount t
RoseWind [281]

Answer:

Step-by-step explanation:

we subtract to find how much they saved, 40-24=16

now we divide 16 by 40 to get the percent 16/40 = 0.4

40%

3 0
3 years ago
The function f(x) = 2x + 210 represents the number of calories burned when exercising, where x is the number of hours spent exer
babymother [125]

Hey there!

When we say (f + g)(2), we are adding both functions together and plugging in 2 for x.

Since f(x) is equal to 2x + 210 and g(x) is equal to 2x + 125, (f + g)(x) is equal to (2x + 210) + (2x + 125).

That can be simplified to 4x + 335.

So, (f + g)(x) = 4x + 335.

Let's plug 2 in for x and solve.

(f + g)(2) = 4(2) + 335

Multiply.

(f + g)(2) = 8 + 335

Add.

(f + g)(2) = 343

The x value is consistent for the values of both equations, in both x is defined as the number of hours spent exercising.

So, (f + g)(2), which is 343, is the amount of calories burned and the calorie deficit on a diet when 2 hours are spent exercising.

Hope this helps!

6 0
3 years ago
Read 2 more answers
46.The function f graphed above is the function f(x) = log2(x) + 2 for x > 0. Find a formula for the inverse of this function
pantera1 [17]

Answer:

The inverse for log₂(x) + 2  is - log₂x + 2.

Step-by-step explanation:

Given that

f(x) = log₂(x) + 2

Now to find the inverse of any function we put we replace x by 1/x.

f(x) = log₂(x) + 2

f(1/x) =g(x)= log₂(1/x) + 2

As we know that

log₂(a/b) = log₂a - log₂b

g(x) = log₂1 - log₂x + 2

We know that  log₂1 = 0

g(x) = 0 - log₂x + 2

g(x) =  - log₂x + 2

So the inverse for log₂(x) + 2  is - log₂x + 2.

3 0
4 years ago
You are reviewing the results of a cohort study of vitamin D supplements and prostate cancer. The study had an alpha level of 0.
SVEN [57.7K]

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

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3 years ago
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