A girl weighs 5/8 as much as her brother does. If the girl weighs 110 lb, how much does her brother weigh?
2 answers:
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Answer:
1)
2)
Where c represent the number of categories c=2
Step-by-step explanation:
Previous concepts
A chi-square goodness of fit test "determines if a sample data matches a population".
A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".
Assume the following dataset:
Tall =30 , Short =20
We need to conduct a chi square test in order to check the following hypothesis:
H0: The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.
H1: The deviations from a 1:1 ratio (25 tall and 25 short) are NOT due to chance.
Part 1
So then we know that the expected values would be 25 for each case
The statistic to check the hypothesis is given by:
And if we replace we got:
Part 2
For this case the degreed of freedom are given by:
Where c represent the number of categories c=2
And we can calculate the p value given by:
And we can find the p value using the following excel code:
"=1-CHISQ.DIST(2,1,TRUE)"
Ok so if I understand this correctly then you have to find out what each one of them are then add them to get the total number of both of them. So this is the equation I did. The one circled on blue is the formula I made for the equation and then the green one is the answer. which is 5 4/9
I hope this helps.
I hope this helps.