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LiRa [457]
3 years ago
11

A girl weighs 5/8 as much as her brother does. If the girl weighs 110 lb, how much does her brother weigh?

Mathematics
2 answers:
fomenos3 years ago
7 0
Brother's weight * 5/8 = 110
Brother's weight * 5/8÷5/8 = 110÷ 5/8
Brother's weight = 176



11Alexandr11 [23.1K]3 years ago
6 0
110 divided by 5 = 22

22 x 8 = 176

176 lbs is the brother's weight
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You move out into the country and you notice every Spring there are more and more Deer Fawns that appear. You decide to try and
marusya05 [52]

Answer: hello your question is incomplete attached below is the missing part

answer : There is no slope

Step-by-step explanation:

To interpret the slope we plot a graph of Winter severity index vs Fawn count

slope = Δy / Δx  = 0

attached below is the graph

There no slope because the graph is a curve and not a straight line graph

3 0
2 years ago
Solve the following system
scZoUnD [109]

Answer:

{x = -4 , y = 2 ,  z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer:  {x = -4 , y = 2 ,  z = 1

4 0
3 years ago
An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t)
beks73 [17]
H(t) = Ho +Vot - gt^2/2

Vo = 19.6 m/s
Ho = 58.8 m
g = 9.8 m/s^2

H(t) = 58.8 + 19.6t -9.8t^2/2 = 58.8 + 19.6t - 4.9t^2

Maximun height is at the vertex of the parabole

To find the vertex, first find the roots.

58.8 + 19.6t - 4.9t^2 = 0

Divide by 4.9

12 + 4t - t^2 = 0

Change sign and reorder

t^2 - 4t -12 = 0 

Factor

(t - 6)(t + 2) =0 ==> t = 6 and t = -2.

The vertex is in the mid point between both roots

Find H(t) for: t = [6 - 2]/2 =4/2 = 2

 Find H(t) for t = 2

H(6) = 58.8 + 19.6(2) - 4.9(2)^2 = 78.4

Answer: the maximum height is 78.4 m
5 0
3 years ago
PLEASE HELP ME ASAP
velikii [3]

Answer:

Radius r=0.30m, Velocity, v=36m/s

(a) angular speed w=

r

v

=

0.3

36

=120rad/s

(b) final angular speed w

′

=0

From rotational kinematics w

′

2

−w

2

=2αθ

0−14400=2α×40×2π

⇒α=

160π

−14400

=−28.6rad/s

2

'Distance covered

=40×2πr

=40×2π×0.3=75.39m

5 0
2 years ago
Which expression is equivalent to 3/2*3/2*3/2*3/2
lesantik [10]

Answer:

hello :

(3/2)×(3/2)×(3/2)×(3/2) = (3/2)^4


8 0
3 years ago
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