Answer:
y < 5
Step-by-step explanation:
22 – 3y > 7
=> 22 – 7 > 3y
=> 15 > 3y
=> y < 5
Therefore, y < 5 is the solution.
Hoped this helped.
The vector AB is not related with the vector CD as k is not the same for each pair of components.
<h3>Are two vectors similar?</h3>
In this question we must prove if the vector AB is a multiple of the vector CD, that is:
![\vec B - \vec A = k \cdot [\vec D - \vec C]](https://tex.z-dn.net/?f=%5Cvec%20B%20-%20%5Cvec%20A%20%3D%20k%20%5Ccdot%20%5B%5Cvec%20D%20-%20%5Cvec%20C%5D)
(1, 4) - (2, 3) = k · [(- 2, 2) - (1, 3)]
(- 1, 1) = k · (- 3, - 1)
Hence, the vector AB is not related with the vector CD as k is not the same for each pair of components.
To learn more on vectors: brainly.com/question/13322477
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Least to greatest: 5 10/11 , 5.822 , 5.84, 117/20.
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Measurement of "AC" :
(x + 5) + (2x <span>− 11) ;
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Find the measurement of "AB" [which is: "(x+5)" ]:
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First, simplify to find the measurement of "AC" :
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</span>(x + 5) + (2x − 11) ;
= (x + 5) + 1(2x − 11) ;
= x + 5 + 2x − 11 ;
→ Combine the "like terms" ;
x + 2x = 3x ;
5 − 11 = - 6 ;
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to get: 3x − 6 ;
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So, (x + 5) + (2x − 11) = 3x − 6 ;
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Solve for: "(x + 5)"
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We have:
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(x + 5) + (2x − 11) = 3x − 6 ;
Subtract: "(2x − 11)" ; from EACH SIDE of the equation ;
to isolate "(x + 5)" on one side of the equation;
and to solve for "(x + 5)" ;
________________________________________________________
→ (x + 5) + (2x − 11) − (2x − 11) = (3x − 6) − (2x − 11) ;
→ (x + 5) = (3x − 6) − (2x − 11) ;
_________________________________________________
Note: Simplify: "(3x − 6) − (2x − 11)" ;
→ (3x − 6) − (2x − 11) ;
= (3x − 6) − 1(2x − 11) ;
= 3x − 6 − 2x + 11 ;
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→ Combine the "like terms" :
_____________________________
+3x − 2x = 1x = x ;
-6 + 11 = 5 ;
_____________________________
To get: x + 5 ;
So we have:
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x + 5 = x + 5 ;
______________________________
So, x = all real numbers.
x = <span>ℝ </span>
