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2 years ago

Solve the system using substitution 3x - 6y =30 y = -6x + 34

Mathematics

2 answers:

salantis [7]2 years ago

7 0

x = 6

y = -2

(explanation in image)

bixtya [17]2 years ago

5 0

Answer:

<h3>then solve for y as a linear equation</h3>

Step-by-step explanation:

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Points N and R both lie on circle O. Line segment RQ is tangent to the circle at point R.

4vir4ik [10]

Answer:

15.0

Step-by-step explanation:

Let's start by looking at triangle ORQ. Since RQ is tangent to the circle, we know that angle ∠ORQ is 90°. Then, since OR is equivalent to the radius of 5, RQ is 5√3, and side OQ is clearly larger than RQ, we can identify this as a 90-60-30 degree triangle. This makes side OQ have a length of 10, and angle ∠QOR, opposite of the second largest side, has the second largest angle of 60°, leaving ∠OQR with an angle of 30°.

The formula for the chord length is 2r*sin(c/2), with c being the angle between the two points on the circle (in this case, ∠QOR=∠NOR).. Our radius is 5, so the length of chord NR is 2*5*sin(60/2)=5, making our answer 5(ON)+5(OR)+5(RN)

4 0

3 years ago

Read 2 more answers

Help pleaseeeeeeeeeeeeee

Kaylis [27]

Answer:

with what

Step-by-step explanation:

5 0

3 years ago

Luke saves 10p coins and 20p coins he has 3 times as many 10p coins as 20p coins a total of 17 pounds how 10p coins does he have

Lena [83]

Answer:

10p coins does he have 102

Step-by-step explanation:

given data

saves= 10p coins and 20p coins

total = 17 pounds

to find out

how 10p coins does he have

solution

we consider here no of 20p coin = x

so equation will be here

3 × 10 x +20 x = 1700

30 x + 20 x = 1700

x = 34

so that

10p coins = 3 time × 34 = 102

20p coins = 34

so that 10p coins does he have 102

5 0

3 years ago

Read 2 more answers

Can someone help me from 18-21

evablogger [386]

#18 answer is 52

#19 answer is 152,100

and I cant make out the rest can you please write them in the comments of this answer?

7 0

3 years ago

A major hurricane is a hurricane with wind speeds of 111 miles per hour or greater. During the 20th century the mean number of t

Bas_tet [7]

Answer:

a) 0.3293 = 32.93% probability that the number of major hurricane to strike U.S mainland in any any give year is exactly one.

b) 0.878 = 87.8% probability that the number of major hurricane to strike U.S mainland in any any give year is at most one.

c) 0.122 = 12.2% probability that the number of major hurricane to strike U.S mainland in any any give year is more than one.

Step-by-step explanation:

We have the mean during an interval, which means that the Poisson distribution is used to solve this question.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

During the 20th century the mean number of the major hurricanes to strike U.S mainland per year was 0.6.

This means that $\mu = 0.6$

Find the probability that the number of major hurricane to strike U.S mainland in any any give year is:

a) Exactly one

This is P(X = 1). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 1) = \frac{e^{-0.6}*0.6^{1}}{(1)!} = 0.3293$

0.3293 = 32.93% probability that the number of major hurricane to strike U.S mainland in any any give year is exactly one.

b) At most one

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

Then

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.6}*0.6^{0}}{(0)!} = 0.5488$

$P(X = 1) = \frac{e^{-0.6}*0.6^{1}}{(1)!} = 0.3293$

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.5488 + 0.3292 = 0.878$

0.878 = 87.8% probability that the number of major hurricane to strike U.S mainland in any any give year is at most one.

c) More than one

This is:

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.878 = 0.122$

0.122 = 12.2% probability that the number of major hurricane to strike U.S mainland in any any give year is more than one.

6 0

3 years ago