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3 years ago

At Norman's Newsstand, 5 magazines cost $10.00. How many magazines could you buy with $24.00?

Mathematics

2 answers:

kow [346]3 years ago

6 0

Answer: you could buy 12 magazines

Step-by-step explanation:

each magazine is $2

Feliz [49]3 years ago

4 0

Answer:

If 5 magazines = $10.00

Then,

10. 20

20.30

Step-by-step explanation:

the answer would be 15

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3 years ago

What is the value of 30-(-45) ?

zlopas [31]

<h2>Answer:</h2>

<h2>Step-by-step explanation:</h2>

$30 - ( - 45) \\ \\ 30 + 45 \\ \\ 75$

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3 years ago

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PLEASE ANSWR DUE BY 11:59 P.M TODAY 50 POINTS

hoa [83]

Answer:

1) 1/4

3) 1/12

4) 5/6

Step-by-step explanation:

1) P(Red) = 1/4

4 options out of which 1 is red

Black --> Black, White, Yellow

Green --> Black, White, Yellow

Red --> Black, White, Yellow

White --> Black, White, Yellow

First 4 branches for buttons.

From each of these 4 branches, make 3 further branches for ribbons

3) In the tree diagram, there are

12 (4×3 = 12) equally likely outcomes

Out of which 1 is (Black, Black)

So, P(Black & Black) = 1/12

4) out of the 12 outcomes, only 2 have same colour of bottom ribbon:

(Black, Black) & (White,White).

Other 10 have different colours.

P(different) = 10/12 = 5/6

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3 years ago

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ZanzabumX [31]

Answer:

Step-by-step explanation:

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3 years ago

Find all values of m so that the function y= e^mx is a solution of the given differential equation.

son4ous [18]

Answer:

m = - 2 is the value of m that the function y= e^mx is a solution of the differential equation, y' + 2y = 0.

Step-by-step explanation:

To determine all values of m so that the function y= e^mx is a solution of the given differential equation.

First, we will find y'.

From, y= e^mx

$y = e^{mx}$

But, $y' = \frac{d}{dx}y$

Hence,

$y' = \frac{d}{dx}e^{mx}\\$

∴ $y' = me^{mx}$

Now, we will put the values of y' and y into the given differential equation y' + 2y =0

From the question,

$y = e^{mx}$

and

$y' = me^{mx}$

Then, $y' + 2y =0\\$ becomes

$me^{mx} + 2(e^{mx}) = 0$

Then, $me^{mx} = - 2(e^{mx}) \\\\$

$m = \frac{-2(e^{mx}) }{e^{mx} } \\$

∴ $m = -2$

Hence, m = - 2 is the value of m that the function y= e^mx is a solution of the differential equation, y' + 2y = 0.

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3 years ago