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kykrilka [37]
2 years ago
13

Solve 7 2 3 − ( 1 2 4 + 3 6 8 ) . Choose the number to complete the mixed number. Numbers may be used once or not at all. ASAP p

ls

Mathematics
1 answer:
weqwewe [10]2 years ago
6 0

Answer:

2\frac{5}{12} <em>is your answer.</em>

Step-by-step explanation:

7\frac{2}{3} -(1\frac{2}{4} +3\frac{6}{8} )\\\\\frac{23}{3} -(\frac{6}{4} +\frac{15}{4}) \\\\\frac{23}{3} -(\frac{21}{4})\\\\\frac{92-63}{12} \\\\\frac{29}{12} \\\\2\frac{5}{12}

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Write an example of a trinomial that cannot be factored.
OverLord2011 [107]

Answer:

x^{2} + x + 1

Step-by-step explanation:

a trinomial that cannot be factored has no real roots.

here is one:

x^{2} + x + 1

After graphing this trinomial has no intersections points with the x-axis wich means it has no roots

5 0
3 years ago
The systematic repayment of a loan through a set number of payments at a
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Answer:

D

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He earns a fixed weekly salary of $300 plus a fee of $5 for each car he parks. His potential earnings for a week are shown in th
tamaranim1 [39]
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3 years ago
Task: Nonpermissible Values for Rational Expressions [30 points] Write a rational expression that has the nonpermissible values
igor_vitrenko [27]

Answer:

A rational expression that has the nonpermissible values x = 0 and x = 17 is f(x) = \frac{4}{x\cdot (x-17)}.

Step-by-step explanation:

A rational expression has a nonpermissible value when for a given value of x, the denominator is equal to zero. In addition, we assume that both numerator and denominator are represented by polynomials, such that:

f(x) = \frac{p(x)}{q(x)} (1)

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If we know that p(x) = 4, then the rational expression is:

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A rational expression that has the nonpermissible values x = 0 and x = 17 is f(x) = \frac{4}{x\cdot (x-17)}.

8 0
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