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Ghella [55]
3 years ago
12

Express the following as an equation where k represents the contestant of the variation​

Mathematics
1 answer:
mojhsa [17]3 years ago
4 0

Answer:

<h2>add me on sñap my ID is: arshad2623f</h2>

<h2>please i just wanted to make friends cuz I'm alone BTW I'm 15yo</h2>
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Luigi is an urban planner. As an independent contractor, he charges a $140 fee plus $25 per hour for
Anuta_ua [19.1K]

Answer:

Function: y=140+25x

Amount earned for 10 hours of work: \$390

Step-by-step explanation:

Let be "x"  the number of hours worked on a project and "y" the total amount Luigi charges for a project.

Based on the data given in the exercise, you can identify that:

  • $140 is a fixed amount.
  • For each hour worked on the project, Luigi charges $25. This can be expressed as: 25x

Then, the total amount he charges for a project is the sum of $140 and 25x. This can be represented with the following function:

y=140+25x

To calculate the amount of money earned for 10 hours of work, you must substitute x=10 into the function and evaluate. Then:

y=140+25(10)\\\\y=390

7 0
3 years ago
.7 pls :P need this so I don’t fail math
Masteriza [31]

Answer:

B

Step-by-step explanation:

distribute 1/2 into 2x and 4, if both sides match then its infinitely many solutions !

7 0
3 years ago
What is the value of sin20sin30sin40sin80.
Ilya [14]
1,-1,1,-1 is your answer
3 0
3 years ago
What is the equation for two thirds of a full turn
wlad13 [49]
Full turn = 360 degrees
2/3 of a full turn.
So 1/3 of a turn is 120 degrees
Since it’s 2/3, you add another 120 to make 240
5 0
3 years ago
Sin0=12/37 find tan0
alexira [117]

Answer:

\large{ \tt{❃ \: EXPLANATION}} :

  • We're provide - Sin θ = \frac{12}{37} which means 12 is the perpendicular & 37 is the hypotenuse [ Since Sin θ = \tt{  \frac{p}{h}} ] . We're asked to find out tan θ ].

\large{ \tt{❁ \: USING \: PYTHAGORAS \: THEOREM}} :

\large{ \tt{❊ \:  {h}^{2}  =  {p}^{2}  +  {b}^{2} }}

\large{ \tt{⇢ {p}^{2} +  {b}^{2}   =  {h}^{2} }}

\large{ \tt{⇢ \:  {b}^{2}  =  {h}^{2}  -  {p}^{2} }}

\large{ \tt{⇢ \:  {b}^{2} = {37}^{2} -  {12}^{2}   }}

\large{ \tt{⇢ \:  {b}^{2}  = 1369 - 144}}

\large{ \tt{ ⇢{b}^{2}  = 1225}}

\large{ \tt{⇢ \: b =  \sqrt{1225}}}

\large{ \tt{⇢ \: b = 35  \: \text {units}}}

  • Now , We know - Tan θ= \tt{ \frac{perpendicular}{base} }. Just plug the values :

\large{ \tt{➝ \: Tan  \: \theta =  \frac{p}{b}  = \boxed{ \tt{  \frac{12}{35} }}}}

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5 0
3 years ago
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