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dlinn [17]
3 years ago
8

Maureen is taking an antibiotic. The table below shows the amount of antibiotic f(t), in mg, that was present in her body after

time t:
t (hours) 1 2 3 4 5
f(t) (mg) 150 90 54 32.4 19.4


Ken was administered 200 mg of the same antibiotic. The amount of antibiotic f(t) in his body after time t is shown by the equation below:

f(t) = 200(0.976)t

Which statement best describes the rate at which Maureen's and Ken's bodies eliminated the antibiotic?
Maureen's body eliminated the antibiotic faster than Ken's body.
Maureen's body eliminated the antibiotic at the same rate as Ken's body.
Maureen's body eliminated the antibiotic at half of the rate at which Ken's body eliminated the antibiotic.
Maureen's body eliminated the antibiotic at one-fourth of the rate at which Ken's body eliminated the antibiotic.
Mathematics
1 answer:
MariettaO [177]3 years ago
3 0
One way to test this is by using the equation for Ken on Maureen. Let's say in the first hour,

f(t) = 200(0.976)^1 = 195.2 mg

In the second hour,

f(t) = 200(0.976)^2 = 190.52 mg

In the third hour,

f(t) = 200(0.976)^3 = 186 mg

If you compare this with Maureen's data which is 150, 90 and 54 for the first, second and third hour, respectively, you will see that Maureen's rate is much faster. However, you cannot tell by what factor because the function is exponential, not a multiple. There is no constant difference between their rates. Therefore, we only know that Maureen's rate is much faster.

The answer is <span>Maureen's body eliminated the antibiotic faster than Ken's body.</span>
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Leo's bank balances at the end of months 1, 2, and 3 are $1500, $1530, and $1560.60,
grandymaker [24]

Leo's balance after 9 months will be: $1757.49

Step-by-step explanation:

It is given that the balances follow a geometric sequence

First of all, we have to find the common ratio

Here

a_1 = 1500\\a_2 = 1530\\a_3 = 1560.60

Common ratio is:

r = \frac{a_2}{a_1} = \frac{1530}{1500} = 1.02\\r = \frac{a_3}{a_2} = \frac{1560.60}{1530} = 1.02

So r = 1.02

The general form for geometric sequence is:

a_n = a_1r^{n-1}

Putting the first term and r

a_n = 1500 . (1.02)^{n-1}

To find the 9th month's balance

Putting n=9

a_9 = 1500 . (1.02)^{9-1}\\= 1500.(1.02)^8\\=1757.4890

Rounding off to nearest hundredth

$1757.49

Hence,

Leo's balance after 9 months will be: $1757.49

Keywords: Geometric sequence, balance

Learn more about geometric sequence at:

  • brainly.com/question/10772025
  • brainly.com/question/10879401

#LearnwithBrainly

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