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Ludmilka [50]
3 years ago
6

11-13 answers plssssss

Mathematics
2 answers:
PtichkaEL [24]3 years ago
7 0
11. The perimeter of A is 16 because 2(5 + 3) = 16.
 The perimeter of B is 44 because 2(11+11) = 44. 
 The perimeter of C is 16 because 2(4 + 4) = 16.
 The perimeter of D is 14 because 2(3 + 4) = 14. 
That means that the perimeter of B is the most since 44 is more than 16 & 14. 

12. Figure C has an area of 108 cm² because 9 x 12 = 108. 

13. Figure A has an area of 40 square ft. The main mass is 8 x 4, which is 32. 
There are 2 smaller squares on the sides, each 2 x 2, which is 8 for both. 
32 + 8 = 40 total square feet. 

Hope this helps!
labwork [276]3 years ago
3 0
For 11, Figure B has the greatest perimeter. For 12, Figure C has an area of 108 square centimeters. For 13, Figure A has an area of 40 square feet. 
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6 0
3 years ago
It costs $x for a round-trip bus ticket to the mall. You have $24. Select an inequality that represents how much money you can s
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4 0
4 years ago
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A box has a volume of 546cm3 and a surface area of 422cm2. What are the Length, Width and Height?
Klio2033 [76]
We know that the formula for the volume of a box is:

V =lwh

Where:
l = length
w = width
h = height

The formula of the surface area of a box is:
SA=2(lw+lh+wh)

Based on the given we know the following:
546cm^{3} =lwh

and

422cm^{2}=2(lw+lh+wh)

If we factor out the given volume, you can come up with 3 numbers that will satisfy the surface area formula:

546=6*7*13

Let:
l = 6cm
w = 7cm
h = 13cm
     
Now let's try this on the surface area formula:
422cm^{2}=2(lw+lh+wh)
422cm^{2}=2((6cm*7cm)+(6cm*13cm)+(7cm*13cm))
422cm^{2}=2(42cm^{2}+79cm^{2}+91cm^{2})
422cm^{2}=2(211cm^{2})
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Any order would be fine.
4 0
3 years ago
I cannot solve this. I don't know how.
Pani-rosa [81]
<h3>Answer:</h3>
  • f(q) = q² -2q +3
  • f(x+h) = (x+h)² -2(x+h) +3
  • (f(x+h) -f(x))/h = 2x -2 +h
<h3>Step-by-step explanation:</h3>

The notation f(x) means you have a function that has been given the name f, and it makes use of the variable x. The variable in the parentheses is called the "argument" of the function f.

(a) To find f(q), you put q everywhere x is in the function equation. This is called evaluating the function for an argument of "q". In the following, note that we have simply changed x to q. (It's really that simple.)

... f(q) = q² -2q +3

(b) As in the previous case, we replace x with (x+h) everywhere.

... f(x+h) = (x+h)² -2(x+h) +3

You can multiply it out, but there appears to be no need to do so for this part of the question.

(c) The intent here is that f(x+h) and f(x) will be replaced by their values and the whole thing simplified. This requires you  expand the expression you see in part (b), subtract f(x), collect terms, and divide the whole thing by h. You have to make use of what you know about multiplying binomials.

We can do it in parts:

... f(x+h) = (x+h)² -2(x+h) +3

... = (x² +2xh +h²) + (-2x -2h) +3

Separating the h terms, this looks like ...

... = (x² -2x +3) + (2xh -2h +h²)

Now, we can finish the numerator part of the expression by subtracting f(x):

... f(x+h) -f(x) = (x² -2x +3) +(2xh -2h +h²) -(x² -2x +3)

You can see that the stuff in the first parentheses matches that in the last parentheses, so when we subtract the latter from the former, we get zero. We are left with only the terms containing h.

... f(x+h) -f(x) = 2xh -2h +h²

To finish up this problem, we need to divide this numerator value by the denominator h.

... (f(x+h) -f(x))/h = (2xh -2h +h²)/h

... = (2xh)/h -(2h)/h +h²/h

... = 2x -2 +h . . . . . this is the value of the expression

... (f(x+h) -f(x))/h = 2x -2 +h

4 0
3 years ago
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