7*6*x^-8*x^3
42x^-8+3 (bases same powers add)
42x^-5
1/42x^5
<span>so the simplified </span>form<span> of 7x^-8*6x^3 is=1/42x^5</span>
In analytical geometry, we can find the linear distance between two parallel lines by determining the coefficients of the variables and the constants. The general equation for a linear equation is: Ax + By = C.
Line 1: 2x - 3y = -4
Line 2: 2x - 3y = -15
In this case, A=2 and B=-3. The constants are C₁ = -4 and C₂ = -15. The distance follows this formula:
d = |C₁ - C₂|/(√(A²+B²)
d = |⁻4 - ⁻15|/(√(2²+⁻3²)
d = 3.051 units
Answer:
$35
Step-by-step explanation:
If $21 is 60% of the original price, then the original price is ...
21 = 0.60p
21/0.60 = p = 35
The original price is $35.00.
Greatest common factor, as it is the greatest common factor of 44 and 12, and it was factored out.
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