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Andreas93 [3]
2 years ago
8

Which is an x-intercept of the continuous function in the table?(0, –6)(3, 0)(–6, 0)(0, 3)

Mathematics
1 answer:
Neporo4naja [7]2 years ago
6 0

Answer:

B. (3,0)

Step-by-step explanation:

The x-intercept is the point where the graph of the function meets the x-axis.

At x-intercept, <u>y = 0 or f(x) = 0</u>

So look through the table and find where <u>f(x) = 0.</u>

From the table, <u>f(x) = 0 at x = 3.</u>

We write this as an ordered pair.

Therefore the x-intercept is <u>(3,0)</u>

The correct choice is <u>B</u>.

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Vlad1618 [11]

Answer:

4 r^3

Step-by-step explanation:

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6 0
1 year ago
NEED HELP ASAP!!!!!!!!!!!!!!!!
salantis [7]

9514 1404 393

Answer:

  (b) (-5, 1)

  (c) (5, -7)

  (d) (9, -2)

Step-by-step explanation:

The coordinate differences between the given points are ...

  (4, 2) -(0, -3) = (4, 5)

The length of the line segment between the points is √(4² +5²) = √41, so this is the side of the square, not a diagonal.

The other four points that could be corners of the square are these same distances, but at right angles. To get points at right angles, the distance values can be swapped, and one of them negated.

Two of the points could be ...

  (4, 2) ± (5, -4) = (9, -2) or (-1, 6)

and the other two could be ...

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5 0
2 years ago
Express 0.96 as a fraction
svp [43]
Since 6 is in the hundredths place,

96/100

You can divide that by two for a different, but equal fraction.

48/50, 24/25

24/25 is the simplest form.

I hope this helped you!
~kaikers
4 0
2 years ago
How many unique ways are there to arrange the letters in a word OPAL.
jek_recluse [69]

Answer:

24.

Step-by-step explanation:

We can use the factorial function to find the number of unique arrangements in a word.

There are 4 unique characters in 'OPAL'. As such, 4! = 24.

In the case that there were repeating characters, such as 'OPALA', then we would divide by the factorial of the number of repeating letters. That looks something like this:

\frac{5!}{2!} = 60

Hope this helped.

7 0
2 years ago
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