25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer:
Step-by-step explanation:
hello :
x+6 because : (x+6)(x+1) =x²+x+6x+6=x² + 7x + 6)
in simplist form it should be 3x+16
Answer:
22.9 ft
Step-by-step explanation:
the height of the wall that reached by the ladder = √ (25²-10²)
=√(625-100)
=√525
= 22.9 ft
