Two complementary angles add up to 90 degrees. Hence, the problem can be set up and solved. Let x represents one angle and 5x represent the angle that is 5 times greater:x + 5x = 90 (simplify)6x = 90 (next divide both sides by 6 to find the value of x [the smaller angle])x = 15 (this is the smaller angle, next subtract 15 from 90 to find the greater angle)90 - 15 = 75 (this is the greater angle which is 5 times that of its complement) <span>90 take away 73...</span>
Let X be the number of lightning strikes in a year at the top of particular mountain.
X follows Poisson distribution with mean μ = 3.8
We have to find here the probability that in randomly selected year the number of lightning strikes is 0
The Poisson probability is given by,
P(X=k) =
Here we have X=0, mean =3.8
Hence probability that X=0 is given by
P(X=0) =
P(X=0) =
P(X=0) = 0.0224
The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224
Answer:
<h3>18 litres</h3>
Step-by-step explanation:
The formula for the remaining volume of fuel in a car's tank is expressed as;
V = I - E.D
where;
I is the initial volume of fuel,
E is the fuel efficiency, and;
D is the distance traveled.
Given
I = 30 litres
1m³ = 1000L
x = 30L
x = 30/1000
x = 0.03m³
I = 0.03m³
E = 100cm³/km
E = 100*10^-6m³/km
E = 10^-4m³/km
E = 10^-4m³/1000m
E = 10^-7m²
D = 120km
Convert km to metres
D = 120km = 120,000m
Substitute the results into the formula;
V = I - E.D
V = 0.03 - (10^-7)(120,000)
V = 0.03 - 0.012
V= 0.018 m³
Convert 0.018 m³ to litres
Since 1 m³ = 1000L
0.018 m³ = y
cross multiply;
y = 1000 * 0.018
y = 18 litres
Hence volume of fuel that remains in Carson's tank by the end of the drive is 18 litres