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stiks02 [169]
3 years ago
6

Leah loves chicken wings and is comparing the deals at three different restaurants. Buffalo Bills has 8 wings for $7. Buffalo Mi

ld Wings has 12 wings for $10. Wingers has 20 wings for $17.
Which restaurant offers the lowest price per wing?
Mathematics
2 answers:
Natali5045456 [20]3 years ago
8 0
Buffalo Wings : 
8 wings = $7
1 wing = $7 ÷ 8 = $0.875

Buffalo Mild Wings :
12 wings = $10
1 wing = $10 ÷ 12 = $0.833

Wingers:
20 wings = $17
1 wing = $0.85

----------------------------------------------------------------------------------
Answer: Buffalo Mild Wings has the cheapest price per wing.
-----------------------------------------------------------------------------------
SSSSS [86.1K]3 years ago
8 0
It would be .88 cents. How I got my answer would be:

I divided 7 by 8

Then my answer came out to a decimal (.875) and I rounded up to the nearest whole cent

And I got .88
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(15, 31) is rotated 90 ° counterclockwise which coordinates gives me
dezoksy [38]

Answer:

(-31,15)

Step-by-step explanation:

Rotating 90 degrees clockwise is very simple:

(a,b) 90 degrees= (-b,a)

Very simple.

Just switch sides and add negative to the first term.

4 0
3 years ago
To avoid modeling the physical characteristics of wheel encoders such the square wave outputs, it is desirable to generate encod
grandymaker [24]

Answer:

The probability distribution is  Normal continuous

Step-by-step explanation:

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5 0
2 years ago
What is 859 under a thousand as a mixed number?
Semmy [17]
To convert the improper fraction \frac{1000}{859} into a mixed number, you first want to divide the numerator (1000) by the denominator (859):
1000 \div 859 = 1 R141

The quotient, which is 1, will be your whole number part of your mixed number. The remainder, 141, will become the numerator of the fraction part of your mixed number. The original denominator of your improper fraction, 859, is still the denominator of your mixed number. So your mixed number form of your improper fraction is:
\frac{1000}{859} = 1 \frac{141}{859}

Your answer is 1 \frac{141}{859}

6 0
2 years ago
The current population of a town is 10,000. If the population, P, increases by 20% each year, which equation could be used to fi
frozen [14]

Answer:

<u>The equation would be:</u>

<u>p = 10,000 * (1 + 0.2)∧ t</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Current population of a town = 10,000 inhabitants

Growth rate of the population = 20% annually

2. Which equation could be used to find the population after T years?

p = Population of the town after t years

t = Number of years

We will use the following equation:

<u>p = 10,000 * (1 + 0.2)∧ t</u>

For example, let's calculate the population after 6 years, replacing with the real values, we have:

p = 10,000 * (1 + 0.2)⁶

p = 10,000 * 2.986

p = 29,860 inhabitants

7 0
3 years ago
How do you do this equation
RUDIKE [14]
When you solve, a quadratic formula is set up as ax^2+bx+c so in this scenario a is 1, b is -1 and c is -6.
-(-1)+- √- 1^2-4(1)(-1)/2(1) is
1+/-√1+4/2 equals -2 and 3 making the answer c
4 0
2 years ago
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