The distance between the two points (-1, 4) and (5, 4) is 6 units.
<u>Step-by-step explanation:</u>
The given Coordinate points are (-1, 4) and (5, 4).
The points are considered as (x1,y1) and (x2,y2).
Here,
x1 = -1 and x2 = 5
y1 = 4 and y2 = 4
<u>The distance formula is given by :</u>
Distance = 
<u>To find the distance between these two points :</u>
The distance formula is used,
Distance = 
⇒ √(6)²
⇒ √36
⇒ 6
Therefore, the between the points is 6 units.
Answer:
C
Step-by-step explanation:
∠ AFD = ∠ AFB + ∠ BFC + ∠ CFD
The 3 angles form a straight angle and sum to 180°, that is
4x + 5 + 6x + 3 + 5x + 7 = 180, that is
15x + 15 = 180 ( subtract 15 from both sides )
15x = 165 ( divide both sides by 15 )
x = 11
∠ CFD = 5x + 7 = 5(11) + 7 = 55 + 7 = 62°, thus
∠ AFE = ∠ CFD = 62° ( vertical angles are congruent )
Answer:
Y=mx+b
Step-by-step explanation:
mx = slope
b = intercept (the place where the line hits the y axis)
The relative change is 2%.
<h3>What is relative change?</h3>
In contrast to the reference value, the absolute change's size is expressed as a fraction called the relative change: relative change = absolute change reference value = new value reference value reference value. The absolute change is expressed as a percentage of the value of the indicator in the prior period, or "relative change" expresses the absolute change as such. When measuring indicators in percentage terms, such as the unemployment rate, absolute and relative change principles also apply. To determine the absolute change, subtract the starting value from the ending value. Simply deduct 1,000 from 1,100 to arrive at 100 in the example. The student population increased by 100 pupils throughout the course of the year because this is the absolute change.
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Answer: 0.9088
Step-by-step explanation:
Given : 
Let x be a random available that represents the proportion of students that reads below grade level .
Using
, for x= 0.36 , we have
Using standard normal z-value table,
P-value
[Rounded yo the nearest 4 decimal places.]
Hence, the probability that a second sample would be selected with a proportion less than 0.36 = 0.9088