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Simora [160]
3 years ago
7

Given the piecewise function below, select all of the statements that are true. f(x)= {-x + 1, x < 0} {-2, x = 0} {x^2 - 1, x

> 0}
Mathematics
1 answer:
Elza [17]3 years ago
8 0

Answer:

this can't even be caculated

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NEED HELP ASAP | 25+ POINTS | IM BEGGING PLZ HELP | I NEED HELP NOW!!
Nady [450]

Answer:

  • 14 ft and 30 ft

Step-by-step explanation:

<u>Perimeter is</u>

<em>P = 2(l+w), where l= length, w = width</em>

  • P = 88
  • l = w + 16

<u>Substitute values to find the value of w:</u>

  • 88 = 2(w + 16 + w)
  • 2w + 16 = 44
  • 2w = 28
  • w = 14

Then

  • l = 14 + 16 = 30

Dimensions are 14 ft and 30 ft

8 0
4 years ago
Read 2 more answers
1) −6k + 7k 2) 12r − 8 − 12 3) n − 10 + 9n − 3 4) −4x − 10x
crimeas [40]

Step-by-step explanation:

I assume we are simplifying

1) -6k+7k = k

2) 12r-8-12 = 12r-20

3) n-10+9n-3 = 10n-13

4) -4x-10x = -14x

7 0
3 years ago
write a short note to a friend explaining when to reverse the inequality when you are solving an inequality
Liula [17]
You reverse the inequality when you divide both sides by a negative number.
example:
-5x>45 (you divide both sides here by -5 to get the value of x)
answer:
x<9 (notice inequality has been has been reversed)
3 0
4 years ago
Find the value of x for which x²-3x - 10 /<br>x² + 12x + 36<br>is equal to zero, undefined​
GREYUIT [131]

Answer:

x= -6 twice

Step-by-step explanation:

x^2-3x-10/x^2+12x+36

By using undefined fraction we only take the denominator and equate it to 0

x^2+12x+36=0

x^2+6x+6x+36=0

(x^2+6x)+(6x+36)=0

x(x+6)+6(x+6)=0

(x+6)(x+6)=0

x+6=0 or x+6=0

x= -6 or x= -6

therefore x= -6 twice

6 0
4 years ago
A company is constructing an open-top, square-based, rectangular metal tank that will have a volume of 64 ft3. what dimensions y
Doss [256]

To solve this problem you must apply the proccedure shown below:

1. You must use the formula for calculate the surface area and the volume of the tank:

1) SA=x^{2} +4xy\\ 2) V=x^{2} y\\ 64=x^{2} y

2. Solve for y in the second equation and substitute it into the first one.Then, you have:

y=\frac{64}{x^{2}}  \\ SA=x^{2} +4x(\frac{64}{x^{2}})

3. Now, derivate:

SA'=2x-256x^{-2} \\ 2x-256x^{-2}=0

4. When you solve for x, you obtain:

2x^{3}-256=0\\ x=\sqrt[3]{\frac{256}{2}}  \\ x=5.03

5. Now, you must calculate y:

y=\frac{64}{(5.03)^{2}} \\ y=2.52

Therefore, the dimensions are:

The sides of the base of the tank: 5.03 feet

The height of the tank: 2.52 feet

8 0
3 years ago
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