Answer:
The center is at (0,0)
The vertices are at ( (
±2 sqrt(2),0)
foci are (
±sqrt(5),0)
Step-by-step explanation:
3x^2 + 8y^2 = 24
Divide each side by 24
3x^2 /24 + 8y^2/24 = 24/24
x^2/8 + y^2 /3 = 1
The general equation of an ellipse is
(x-h)^2/ a^2 + (y-k)^2 / b^2 = 1
a>b (h,k) is the center
the coordinates of the vertices are (
±a,0)
the coordinates of the foci are (
±c,0), where ^c2=a^2−b^
2
The center is at (0,0)
a = sqrt(8) = 2sqrt(2)
The vertices are at ( (
±2 sqrt(2),0)
c = 8 - 3 =5
foci are (
±sqrt(5),0)
Answer:
∠RST = 6x - 18
Step-by-step explanation:
Since SQ bisects ∠TSR then ∠RSQ = ∠QST = 3x - 9
and ∠RST = ∠RSQ + ∠QST = 3x - 9 + 3x - 9 = 6x - 18
Answer:
-3
Step-by-step explanation:
double negative = positive so the equation turns into -8+5. add 5 by going 5 spaces closer to 0 on a number line. the answer is -3.
another equation is -3-5=-8
hope this helped! =)
There are a lot i don't think that question is answerable there are too many to count.but there are more than 99
