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2 years ago

Find the difference, –8 – (–5). Then check your work by writing the equivalent addition sentence.

Mathematics

1 answer:

pav-90 [236]2 years ago

4 0

Answer:

-3

Step-by-step explanation:

double negative = positive so the equation turns into -8+5. add 5 by going 5 spaces closer to 0 on a number line. the answer is -3.

another equation is -3-5=-8

hope this helped! =)

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How did you get the five consecutive integer that have a product of 524,160

a_sh-v [17]

12*13*14*15*16 = 524160

Idk how to get this answer actually. It's just my first guess, and it happened to be right.

7 0

3 years ago

(08.03) Consider the following pair of equations:

Luba_88 [7]

Substitution method is used to solve the linear system of equations for one or more variables.

Consider the first equation y = 3x + 3 -----(1)

In equation (1) plug in y=x-1, we get

x -1 = 3x + 3

Add -3x on both side , we get

x-3x -1 = 3x-3x +3

-2x-1=0 + 3

Now add +1 on both sides, we get

-2x-1+1= 3+1

-2x + 0 =4

Now divide both side by -2

-2x/-2= 4/-2

X= -2

Now put x=-2 in the the second equation,

y=x-1

y=(-2)-1

y=-3

Solution(-2,-3)

6 0

3 years ago

Look at the pic plsssss help

Tresset [83]

Answer:

I think its b

Step-by-step explanation:

please tell me im incorrect c:

3 0

3 years ago

Read 2 more answers

Solve (x + 1)2 – 4(x + 1) + 2 = 0 using substitution.

solniwko [45]

For this case we have to:

Let $u = x + 1$

So:

$u ^ 2-4u + 2 = 0$

We have the solution will be given by:

$u = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}$

Where:

$a = 1\\b = -4\\c = 2$

Substituting:

$u = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (2)}} {2 (1)}\\u = \frac {4 \pm \sqrt {16-8}} {2}\\u = \frac {4 \pm \sqrt {8}} {2}\\u = \frac {4 \pm \sqrt {2 ^ 2 * 2}} {2}\\u = \frac {4 \pm2 \sqrt {2}} {2}$

The solutions are:

$u_ {1} = \frac {4 + 2 \sqrt {2}} {2} = 2 + \sqrt {2}\\u_ {2} = \frac {4-2 \sqrt {2}} {2} = 2- \sqrt {2}$

Returning the change:

$2+ \sqrt {2} = x_ {1} +1\\x_ {1} = 1 + \sqrt {2}\\2- \sqrt {2} = x_ {2} +1\\x_ {2} = 1- \sqrt {2}$

Answer:

$x_ {1} = 1 + \sqrt {2}\\x_ {2} = 1- \sqrt {2}$

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3 years ago

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What is the volume of a cylinder with 14 ft and 9ft

zlopas [31]

It’s V = radus hight

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3 years ago