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Kay [80]
2 years ago
10

Need help asap please show work

Mathematics
1 answer:
kvv77 [185]2 years ago
4 0

Answer:

m<5= 75° Alternate angles are equal

m<6 = 180°-75°= 105 ° Angles on a straight line adds up to 180°

In a rectangle opposite sides are equal so AB= CD

2x+8= 3x+4

3x-2x=8-4 ( combine like terms, the signs will change since they are going over opposite sides)

x= 4

To solve for BC

AD= BC

x+17 ( we know that x=4)

4+17=21

Therefore BC= 21

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Help is very much needed!
Arisa [49]
Multiply -3 times three and then multiply that by 5 the answers is -45
8 0
3 years ago
Read 2 more answers
If x=5, what is the perimeter of the rectangle whose length is 6x-4 and whose width is 3x+2? *
strojnjashka [21]

Answer:

86

Step-by-step explanation:

Given, x = 5

length of a rectangle = 6x-4 = 6 * 5 - 4 = 30-4 = 26

width of a rectangle = 3x + 2 = 3 * 5 + 2 = 15 + 2 = 17

Now , finding the perimeter of the rectangle :

Perimeter of a rectangle = 2 ( length + width )

                                          = 2 ( 26 + 17 )

                                          = 2 * 43

                                         = 86

Hope I helped!

Best regards !

- TheAnimeGirl

8 0
3 years ago
The following table shows the speeds at which Jeff does 4 activities. For example, biking has a rate of 19 miles in 2 hours. Whi
ExtremeBDS [4]

The type of activity that Jeff does at a speed of 4.5 miles per hour is Swimming

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem !

<em>This problem is about Kinematics.</em>

We will solve it in the following way

\texttt{Speed of Biking} = \texttt{Distance of Biking} \div \texttt{Time Taken}

\texttt{Speed of Biking} = \texttt{19} \div \texttt{2}

\texttt{Speed of Biking} = 9.5 \texttt{ miles per hour}

\texttt{ }

\texttt{Speed of Walking} = \texttt{Distance of Walking} \div \texttt{Time Taken}

\texttt{Speed of Walking} = \texttt{14} \div \texttt{4}

\texttt{Speed of Walking} = 3.5 \texttt{ miles per hour}

\texttt{ }

\texttt{Speed of Running} = \texttt{Distance of Running} \div \texttt{Time Taken}

\texttt{Speed of Running} = \texttt{15} \div \texttt{3}

\texttt{Speed of Running} = 5 \texttt{ miles per hour}

\texttt{ }

\texttt{Speed of Swimming} = \texttt{Distance of Swimming} \div \texttt{Time Taken}

\texttt{Speed of Swimming} = \texttt{18} \div \texttt{4}

\texttt{Speed of Swimming} = \boxed{4.5 \texttt{ miles per hour}}

\texttt{ }

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

3 0
3 years ago
Read 2 more answers
Please help me with my math! Thank you!
tangare [24]

Answer:

c determine the side length of one tablecloth correct to the nearest tenth of a meter

3 0
3 years ago
5. I need help with question in the attached picture!
igomit [66]

ANSWER

x=100,y=10

EXPLANATION

The given logarithmic equations are;

log_{10}( {x}^{2}  {y}^{3} )  = 7

This implies that,

{x}^{2}  {y}^{3}  =  {10}^{7} ...(1)

and

log_{10}( \frac{x}{y} ) = 1

This implies that,

\frac{x}{y}  =  {10}^{1}

x = 10y...(2)

Put equation (2) into equation (1)

{(10y)}^{2}  {y}^{3}  =  {10}^{7}

10 ^{2} y^{2}  {y}^{3}  =  {10}^{7}

{y}^{5}  =  {10}^{5}

Hence y=10.

This implies

x = 10(10) = 100

3 0
3 years ago
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