Question

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 7 kg, the acceleration of the object is $8 m/s^{2}$. If the same force acts upon another object whose mass is 4 kg, what is this object's acceleration?

Answer 1

Answer:

14m/$s^{2}$

Step-by-step explanation:

F = ma

Mass1:   F1 = (7kg)*(8m/$s^{2}$)

Mass2:  F2 = (4kg)*a

The same force, so F1 = F2

(7kg)*(8m/$s^{2}$) = (4kg)*a

a = (7kg)*(8m/$s^{2}$)/(4kg)

a = (7/4)*(8m/$s^{2}$)

a = 14m/$s^{2}$