Question

HELP I'LL MARK BRAINLIEST

Answer 1

Answer:

$\large{\boxed{\sf Hypotenuse = 16.97\ cm }}$

Hypotenuse=16.97 cm

Step-by-step explanation:

Here it is given that the area of a right isosceles ∆ is 72 cm² . Let us assume that each equal side is x . Therefore the height and the base of the ∆ will be same that is x .

p

$\begin{gathered}\sf\qquad\longrightarrow$

Area =

$\dfrac{1}{2}(base)(height)\\\end{gathered}$

⟶Area=21(base)(height)

$\begin{gathered}\sf\qquad\longrightarrow$

$72cm^2=\dfrac{1}{2}(x)(x)\\\end{gathered}$

⟶72cm2=21(x)(x)

$\begin{gathered}\sf\qquad\longrightarrow x^2=$

144cm^2\\\end{gathered}⟶x2=144cm2

$\begin{gathered}\sf\qquad\longrightarrow x$

$=\sqrt{144cm^2}\\\end{gathered}⟶x=144cm2$

$\sf\qquad\longrightarrow \pink{x = 12cm }⟶x=12cm$

Hence we may find hypotenuse using Pythagoras Theorem as ,

$\sf\qquad\longrightarrow h =\sqrt{ p^2+b^2}⟶h=p2+b2$

Here p = b = 12cm ,

$\begin{gathered}\sf\qquad\longrightarrow h$

=\sqrt{ (12cm)^2+(12cm)^2}\\\end{gathered} [/tex]

⟶h=(12cm)2+(12cm)2

$\begin{gathered}\sf\qquad\longrightarrow h$

$=\sqrt{144cm^2+144cm^2}\\\end{gathered}$

⟶h=144cm2+144cm2

$\begin{gathered}\sf\qquad\longrightarrow h$

=\sqrt{288cm^2}\\\end{gathered}⟶h=288cm2

$\sf\qquad\longrightarrow \pink{ hypotenuse=$

16.97cm }⟶hypotenuse=16.97cm

Hence the hypotenuse is 16.97 cm .

[/tex]

Answer 2

Answer:

5 1/2

Step-by-step explanation:

12 3/4 - 7 1/4