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In-s [12.5K]
3 years ago
15

HELP I'LL MARK BRAINLIEST

Mathematics
2 answers:
daser333 [38]3 years ago
6 0

Answer:

\large{\boxed{\sf Hypotenuse = 16.97\ cm }}

Hypotenuse=16.97 cm

Step-by-step explanation:

Here it is given that the area of a right isosceles ∆ is 72 cm² . Let us assume that each equal side is x . Therefore the height and the base of the ∆ will be same that is x .

p

\begin{gathered}\sf\qquad\longrightarrow

Area =

\dfrac{1}{2}(base)(height)\\\end{gathered}

⟶Area=21(base)(height)

\begin{gathered}\sf\qquad\longrightarrow

72cm^2=\dfrac{1}{2}(x)(x)\\\end{gathered}

⟶72cm2=21(x)(x)

\begin{gathered}\sf\qquad\longrightarrow x^2=

144cm^2\\\end{gathered}⟶x2=144cm2

\begin{gathered}\sf\qquad\longrightarrow x

=\sqrt{144cm^2}\\\end{gathered}⟶x=144cm2

\sf\qquad\longrightarrow \pink{x = 12cm }⟶x=12cm

Hence we may find hypotenuse using Pythagoras Theorem as ,

\sf\qquad\longrightarrow h =\sqrt{ p^2+b^2}⟶h=p2+b2

Here p = b = 12cm ,

\begin{gathered}\sf\qquad\longrightarrow h

=\sqrt{ (12cm)^2+(12cm)^2}\\\end{gathered} [/tex]

⟶h=(12cm)2+(12cm)2

\begin{gathered}\sf\qquad\longrightarrow h

=\sqrt{144cm^2+144cm^2}\\\end{gathered}

⟶h=144cm2+144cm2

\begin{gathered}\sf\qquad\longrightarrow h

=\sqrt{288cm^2}\\\end{gathered}⟶h=288cm2

\sf\qquad\longrightarrow \pink{ hypotenuse=

16.97cm }⟶hypotenuse=16.97cm

Hence the hypotenuse is 16.97 cm .

[/tex]

Elina [12.6K]3 years ago
4 0

Answer:

5 1/2

Step-by-step explanation:

12 3/4 - 7 1/4

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