Answer:
105.6
hope this helps
have a good day :)
Step-by-step explanation:
Nancy: 5 Stan: 10
5 is 5 years
younger then Stan
And 5 is twice as
young as 10
down 3 unit mean -3 outside root
right 2 unit mean -2 inside root,
so the answer is

Answer: 300
Step-by-step explanation: 300+200=500
then 500-200=300
Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when
. So






Rouding up
We need a sample size of at least 719