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3 years ago

9

When multiplying and/or dividing fractions, answer if each of the statements below are TRUE or FALSE.

1 answer:

erma4kov [3.2K]3 years ago

6 0

1. Only true to division. Most likely though when multiplying it's more helpful to have the denominators the same.

2. True

3. False

4. True

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In how many ways can a committee of 4 be chosen from a group of 9 people?

QveST [7]

Since this is a combination not a permutation problem, (order does not matter) you should use the "n choose k" formula.

C=n!/(k!(n-k)!) where C is the number of unique combinations, n equals the total number of possible choices and k equals the specific number of choices. In this case:

C=9!/(4!(9-4)!)

C=9!/(4!5!)

C=362880/(24*120)

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So there are 126 unique ways to pick 4 people from a group of 9 people.

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mote1985 [20]

Answer: The equation that represents the other equation is $y=\dfrac{1}{3}x+5$ .

The solution of the system is <u>(3,6).</u>

Step-by-step explanation:

Linear equation: $y=mx+c$ , where m= slope

c = y-intercept.

In the first table, the y-intercept = 5 [ y-intercept = value of y at x=0.

Slope for first table = $\dfrac{y_2-y_2}{x_2-x_1}=\dfrac{6-5}{3-0}=\dfrac{1}{3}$

The equation that represents the first table:

$y=\dfrac{1}{3}x+5$

So, the equation that represents the other equation is $y=\dfrac{1}{3}x+5$ .

Also, the solution of the system is the common point (x,y) that satisfy both equations in the system.

Here, x=3 and y=6 is the common value in both tables.

So, the solution of the system is <u>(3,6).</u>

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