Question

Write the equation of the line given the two points. (4,-3) and (3,1)

Answer 1

Answer:

$y = -4x + 13$

Step-by-step explanation:

First, find the slope (denoted by the variable, m). Use the following equation:

slope $(m) = \frac{y_2 - y_1}{x_2 - x_1}$

Let:

$(x_1, y_1) = (4 , -3)\\(x_2, y_2) = (3 , 1)$

Plug in the corresponding numbers to the corresponding variables:

$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - (-3)}{3 - 4} = \frac{1 + 3}{-1} = \frac{4}{-1} = -4$

Use the slope-intercept form. The slope-intercept form is:

$y = mx + b$

Use one of the given points to plug in for (x ,y). Also note that the slope (m) is equal to -4. Plug in the corresponding numbers to the corresponding variables:

$y = mx + b\\(x , y) = (3 , 1)\\m = -4\\\\\\1 = (-4 * 3) + b\\1 = (-12) + b\\1 (+12) = b - 12 (+12)\\b = 1 + 12\\b = 13$

Plug in the slope (m) and the y-intercept (b) to get your equation:

$y = -4x + 13$

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Answer 2

Answer:

y=-4x+13

Step-by-step explanation:

y=mx+b

slope =

1--3/3-4

4/-1

-4/1

y-1=-4(x-3)

y-1=-4x+12

y=-4x+13