All categories

3 years ago

Find the slope of a line parallel to 3x + y = 15

2 answers:

7 0

Rearranging the equation gives us y=15-3x

if we were to find an equation for a PARALLEL line, we would just use the same slope.

if we were to find an equation for a PERPENDICULAR line, we would do the opposite reciprocal. in this case, that would be answer D. but this is WRONG!

the question asks us to find the slope of a PARALLEL line. thus, the answer is C.

final answer -- C.

Romashka-Z-Leto [24]3 years ago

7 0

I am pretty sure the answer is C but i am not 100% sure

You might be interested in

Four less than the product of one and a number X. <br><br><br> Please help me.

satela [25.4K]

Answer:

x−4

Step-by-step explanation:

3 0

3 years ago

A recipe says that 1 and 3/4 cups of baking soda are needed to make one batch of a homemade cleaning product. How many total cup

givi [52]

Answer:

3.75 cups of baking soda are needed to make 2 and 1/2 batches of the cleaning product

Step-by-step explanation:

This question can be solved by a rule of three.

A recipe says that 1 and 3/4 cups of baking soda are needed to make one batch of a homemade cleaning product.

1 + 3/4 cups = 1 + 0.75 = 1.75 cups for one batch.

How many total cups of baking soda are needed to make 2 and 1/2 batches of the cleaning product?

2 and 1/2 batches is 2 + 0.5 = 2.5 batches.

1.75 cups for one batch. How many cups for 2.5 batches? So

1 batch - 1.5 cups

2.5 batches - x cups

c = 2.5*1.5 = 3.75

3.75 cups of baking soda are needed to make 2 and 1/2 batches of the cleaning product

8 0

3 years ago

Read 2 more answers

I really don't understand number 10 please help

djyliett [7]

Its asking what possible coordinates

8 0

3 years ago

Read 2 more answers

Shau-uen solve the equation 18.5w+6.5w-2.8w=149.1 Her work is shown below

Ghella [55]

The answer is

C.- step 3

5 0

3 years ago

Read 2 more answers

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0

1 year ago