If a capacitor's dielectric constant is vacuum its dielectric constant is k will be equal to 1.
<u>Explanation:</u>
Relative permittivity of a dielectric substance is referred to as its dielectric constant. Relative permittivity/dielectric constant k is a dimensionless quantity that is the ratio of absolute permittivity and vacuum permittivity.
It is given by the expression
k=k=ε /ε0
where ε denotes absolute permittivity and ε0 denotes permittivity of vacuuum.
Absolute permittivity ε of vacuum= ε0
therefore k= ε0/ ε0=1
dielectric constant of vacuum is 1 .
Potential energy , hope this helps :)
Vs - velocity on beginning
ve - velocity on ending. You've got:
So he needed 4 second.
Answer:
6 m/s.
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 4 m/s
Acceleration (a) = 2 m/s²
Distance (s) = 5 m
Final velocity (v) =?
The final velocity of the object can obtained as shown below:
v² = u² + 2as
v² = 4² + (2 × 2 × 5)
v² = 16 + 20
v² = 36
Take the square root of both side.
v = √36
v = 6 m/s
Therefore, the final speed of the object is 6 m/s.
