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nadya68 [22]
3 years ago
9

How many serves are allowed point

Physics
1 answer:
Radda [10]3 years ago
8 0

Answer: All

Explanation:

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An 80 kg astronaut has gone outside his space capsule to do some repair work. Unfortunately, he forgot to lock his safety tether
Anna [14]

Answer:

the time taken by the astronaut to reach safety = 9.8 hr

Explanation:

The equation for intensity can be written as :

I = \frac{P}{A}

where :

\frac{I}{c}= \frac{F}{A}

Replacing that into the above previous equation; we have:

\frac{P}{Ac}=\frac{F}{A}

F = \frac{P}{c}

However ; the force needed to push the astronaut is as follows:

F = ma

where ;

m = mass of the  astronaut and a = its acceleration

we as well say;

\frac{P}{c} = ma

a = \frac{P}{mc}

Replacing P with 1000 W ; m with 80 kg and 3*10^{8} \  m/s for  c

Then; a = \frac{1000 \ W}{(80)(3.0*10^8)}

a = 4.2*10^{-8} \ m/s

It is also known that the battery will run for one hour and after which the battery on the laser will run out

Then to determine the change in the position after the first hour ; we have:

\Delta x_1 = \frac{1}{2}*4.2*10^{-8} \ m/s^2 ) (1.0 \ h)^2

\Delta x_1 = \frac{1}{2}*4.2*10^{-8} \ m/s^2 ) (1.0 *3600 s)^2

= 0.27 m

Furthermore, the final velocity of the astronaut is determined as:

v_1 = at_1

where ;

v_1 = final \ velocity

replacing t_1 = 1.0 \ h and a =  4.2*10^{-8} \ m/s; Then:

v_1 = (4.2*10^8 \ m/s * 1.0 \ h * \frac{ 3600\ s}{1.0 \ h})

v_1 =  1.51 *10^{-4} \ m/s

Also; when he drifted 5.0 m away from the capsule; the distance is far short of the 5 m but he still have 9 hours left of oxygen . In addition to that, he acceleration is also zero and the final velocity remains the same, so:

To find the final distance traveled by the astronaut ;we have:

\Delta x_2 = d - \Delta x_1

where;

\Delta x_2 = the final distance

d = total distance

So;

\Delta x_2 = 5 m - 0.27 m \\ \\ \Delta x_2 = 4.73 \ m

The time taken to reach the final distance can be calculated as:

t_2 = \frac{\Delta x_2 }{v_1}

where;

t_2 = is the  time to  reach the final distance

Replacing 4.73 for {\Delta x_2 } and  1.51*10^{-4} m/s for v_1

t_2 = \frac{4.73 \ m }{1.51*10^{-4} \ m/s}

t_2 = 31500 \ s (\frac{1.0 \ h}{3600 \ s} )

t_2 = 8.8 \ h

We knew the laser was operated for 1 hour; thus the total time taken by the astronaut to  reach the final distance is the sum of the time taken to reach the final distance and the operated time of the laser.

Hence ; the time taken by the astronaut to reach safety = 9.8 hr

8 0
3 years ago
Nathan is walking to the store and sees a snake slithering across the sidewalk. He jumps over it with an initial vertical veloci
Travka [436]

Answer:

0.62\:\mathrm{s}

Explanation:

Since the universal SI unit for velocity is meters/second, let's convert ft/s to m/s:

10\:\mathrm{ft/s}=3.048\:\mathrm{m/s}

We can use the following kinematics equation to solve this question:

v_f=v_i+at

What we know:

  • The initial velocity, v_i, is 3.048\:\mathrm{m/s}
  • (physics concept) The final velocity must be equal in magnitude but opposite in direction to the initial velocity (v_f=-3.048\:\mathrm{m/s})
  • Acceleration, a, is acceleration due to gravity at about 9.8\:\mathrm{m/s}

Solving for t:

-3.048=3.048+(-9.8t),\\-6.096=-9.8t,\\t=\frac{-6.096}{-9.8}\approx \boxed{0.62\:\mathrm{s}}

8 0
3 years ago
Which statement best describes the role of gravity?
andre [41]
D.It draws objects together in proportion to their mass
6 0
4 years ago
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Heat transfer by condution
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Heat Transfer by conduction in solids, convection of fluids (liquids or gases), and radiation through anything that will allow radiation to pass.  if this is not what are you looking for I am sorry :c
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3 years ago
In which situation does the energy constantly change from gravitational potential energy to kinetic energy?
Anarel [89]
 when you drop a ball and let it fall to the ground
4 0
3 years ago
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