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bearhunter [10]
3 years ago
6

Why are experiments often performed in laboratories?

Physics
2 answers:
nekit [7.7K]3 years ago
7 0

Answer:

Experiments are often performed in laboratories because of letter b, you can control more variables more easily. It is because you have enough supplies in the laboratory where it is accessible, making it easy to control and to conduct the experiment that is going to be made. For having an accessible and easy control in variables is essential to do because in creating an experiment, a lot of things are needed and used.

Explanation:

crimeas [40]3 years ago
4 0

Answer:

To keep a steady and stable and consistent environment

Explanation:

becuase

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A net force of 15 N is applied to a cart with a mass of 2.1 kg. a. What is the acceleration of the cart? b. How long will it tak
Gennadij [26K]
The first question's answer is :
If, F=ma
Then, 15N= 2.1kg (a)
15/2.1=a
7.14=a
Therefore, acceleration = 7.14m/s^2

sorry I am not sure about the second question :-(
6 0
3 years ago
A 1kg ball is dropped (from rest) 100m onto a spring with spring constant 125N/m. How much does the spring compress?
Anastasy [175]

Answer:

3.95 m

Explanation:

m = 1 kg, h = 100 m, k = 125 N/m

Let the spring is compressed by y.

Use the conservation of energy

potential energy of the mass is equal to the energy stored in the spring

m x g x h = 1/2 x ky^2

1 x 9.8 x 100 = 0.5 x 125 x y^2

y^2 = 15.68

y = 3.95 m

7 0
4 years ago
What moon phase is shown in the picture ?
Artemon [7]

the answer is waxing gibbous moon

Explanation:

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6 0
3 years ago
What is the magnitude of the force that is exerted on a 20 kg mass to give it an acceleration of 10.0
ANEK [815]

Answer:Mass of the body = 20 kg.

Final Velocity = 5.8 m/s.

Initial velocity = 0

Time = 3 seconds.  

Using the Formula,  

Acceleration = (v - u)/ t

= (5.8 - 0)/ 3

= 1.6 m /s².

Now, Using the Formula,  

Force = mass × acceleration

= 20 × 1.6

=

Explanation: I REALLY  HOPE THIS HELPS I'M KINDA NEW AT THIS :] :]

8 0
3 years ago
A particle (charge = +0.8 mC) moving in a region where only electric forces act on it has a kinetic energy of 6.7 J at point A.
Maksim231197 [3]

Answer:

The kinetic energy of the particle as it moves through point B is 7.9 J.

Explanation:

The kinetic energy of the particle is:

\Delta K = \Delta E_{p} = q\Delta V

<u>Where</u>:

K: is the kinetic energy

E_{p}: is the potential energy

q: is the particle's charge = 0.8 mC

ΔV: is the electric potential = 1.5 kV                                    

\Delta K = q \Delta V= 0.8 \cdot 10^{-3} C*1.5 \cdot 10^{3} V = 1.2 J

Now, the kinetic energy of the particle as it moves through point B is:

\Delta K = K_{f} - K_{i}

K_{f} = \Delta K + K_{i} = 1.2 J + 6.7 J = 7.9 J

Therefore, the kinetic energy of the particle as it moves through point B is 7.9 J.

I hope it helps you!      

8 0
4 years ago
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