An aritmetic sequence is like this

where a1=first term and d=common difference
geometric is

where a1=first term and r=common ratio
can it be both aritmetic and geometric
hmm, that means that the starting terms should be the same
therfor we need to solve

what values of d and r make all natural numbers of n true?
are there values that make all natural numbers for n true?
when n=1, then d(1-1)=0 and r^(1-1)=1, so already they are not equal
the answer is no, a sequence cannot be both aritmetic and geometric
Answer:
(8+t)^2-6 when t=2
Step-by-step explanation:
1: (8+2)^2-6
2: (10)^2-6
3: 100-6
4: 94
Answer:
(8×5)+(10×20)=240
Step-by-step explanation:
8 (Car wash hourly pay $$) times 5 (hours worked) equals 40(money earned). And 10 (dog walker money $$) times 20 (hour worked) equals 200(money earned). 200(dog walker) plus 40(car washer) is 240. So if you do 5 hours at the car wash and 10 hours of dog walking, you'll earn enough to cover your expenses.
1. 14:8, 21:12 28:16
2. 10/12 15/18 20/24
5. 5:4
6. No
7. No
8. Yes
9. No
10. 15