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Dmitriy789 [7]
3 years ago
13

Pythagorean Question

Mathematics
1 answer:
exis [7]3 years ago
3 0
Pythagoras: a squared + b squared = c squared
35^2 (1225) + b squared = 175^2 (30,625)
30,625 - 1225 = 29400
square root 29400 = 171.5 cm
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The volume of a cylindrical container
Ray Of Light [21]

Answer:

A. \frac{3}{4}\textrm{ gal}

Step-by-step explanation:

Given:

Volume of the cylindrical container before dilation, V_{i}=1\textrm{ gal}

Scale factor of the dilation, SF=\frac{3}{4}

Therefore, the volume of the dilated cylinder is given as:

V_{f}=SF\times V_{i}

Plug in 1 gal for V_{i} and \frac{3}{4} for SF. Solve for V_{f}. This gives,

V_{f}=\frac{3}{4}\times 1\\V_{f}=\frac{3}{4}\textrm{ gal}

Therefore, the volume of the dilated cylinder is \frac{3}{4} gallons.

3 0
3 years ago
I’m confused on this one
serious [3.7K]
The answer is 13.

Because this is a kite, the diagonals intersect perpendicularly or with a 90° angle.

In the triangle DIC, which is a right triangle, the legs are 5 and 12. To find the hypotenuse, we use Pythogarean theorem:
{a}^{2}  +  {b}^{2}  =  {c}^{2}
Plug in the givens:
{5}^{2}  +  {12}^{2}  =  {c}^{2}
Take the squares:
25 + 144 = 169  =  {c}^{2}
Take the square root of both sides:
\sqrt{169}  =   \sqrt{ {c}^{2} }  \\  \\ c = 13
We find the line segment DC. In the question it says "BD = DC". So BD is equal to 13.
5 0
3 years ago
I'll give free brainliest to somebody if they heart and give this 5 starts
Gwar [14]
How do i heart this or give 5 stars?
6 0
3 years ago
Read 2 more answers
Find all degree solutions in the interval 0° ≤ θ < 360°. If rounding is necessary, round to the nearest tenth of a degree. Us
xenn [34]

Answer:

\theta_{1} \approx 30.473^{\textdegree}

\theta_{2} \approx 120.473^{\textdegree}

\theta_{3} \approx 210.473^{\textdegree}

\theta_{4}\approx 300.473^{\textdegree}

Step-by-step explanation:

The equation needs to be rearranged in terms of one trigonometric function:

5\cdot \sin 2\theta - 9\cdot \cos 2\theta = 0

5\cdot \tan 2\theta - 9 = 0

5\cdot \tan 2\theta = 9

\tan 2\theta = \frac{9}{5}

\theta = \frac{1}{2}\cdot \tan^{-1} \left(\frac{9}{5} \right)

The tangent function has positive values in the 1st and 3rd Quadrants. Then, the solutions are:

\theta_{1} \approx 30.473^{\textdegree}

\theta_{2} \approx 120.473^{\textdegree}

\theta_{3} \approx 210.473^{\textdegree}

\theta_{4}\approx 300.473^{\textdegree}

3 0
3 years ago
algebra 1. please help me. i’m literally struggling , i’ll give an extra 50 points if it’s right and brainliest. - question in p
ehidna [41]

Answer:

13x^2+2x+5

Step-by-step explanation:

that is the right answer

You have to combine the like terms.

8 0
3 years ago
Read 2 more answers
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