The following set of data represents letter grades on term papers in a rhetoric class: A,A,A,B,B,B,B,C,C,C,C,C,C,C,C,C,D,D,D,F.
Viktor [21]
Answer:
c. Mode
Step-by-step explanation:
Mean is the average obtained by adding all values and then dividing by the size of the values. Here, adding A and B etc is not clear.
Median is the middle value of a set of numeric values. To find a median, values should be sort-able from smallest to the largest. If there is no unique middle value, then the average of the middle values has to be taken. Here, average of the two different grades is not clear.
Mode is the value that occurs most often. Clearly C occurs most often.
Mid-range value is the mean of the difference between largest value and the smallest value. Here, difference between A and F is not clear.
Mean,median,Mid-range are applied to numeric values where mode is also suitable for categorical values.
Therefore, the most appropriate measure of central tendency for the data described is mode
Answer:
finding the number of equal-sized parts into which a number can be split
Step-by-step explanation:
Let us split the number 80 into 10 equal parts.
80 = 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8 + 8
= 8 + 8 + 8 +...to 10 times
= 8(10)
or 
So, if N is any number and p is one of its equal part, then the number of parts into which N is split by p is 
.
Hence, finding the number of equal-sized parts is best modeled with a division expression.
It would be still be X. Any number times 1 is that number. For example 3x1=3 and 325x1=325 :)
A=24
Find the area by multiplying both diagonals and dividing them by 2. Like so: And you might be wondering how to do that. By using the pythagorean theorem and some simple addition, you could get the answer. One diagonal is 8 and the other is 6....so, 8x6=48....48/2=24
Please let me know if you have any other questions!
