Answer:
ΔEFG is an isosceles triangle.
Step-by-step explanation:
Given:
E (0, 0),
F (−7, 4),
G (0, 8)
ΔEFG
Solution:
Distance formula
Distance d = 
Step 1: Finding the length of EF
By using distance formula,



Step 2: Finding the length of FG
By using distance formula,

Step 2: Finding the length of GE

Thus we could see that the sides EF = FG
So it is a isosceles triangle.
Answer:
a) It can be used because np and n(1-p) are both greater than 5.
Step-by-step explanation:
Binomial distribution and approximation to the normal:
The binomial distribution has two parameters:
n, which is the number of trials.
p, which is the probability of a success on a single trial.
If np and n(1-p) are both greater than 5, the normal approximation to the binomial can appropriately be used.
In this question:

So, lets verify the conditions:
np = 201*0.45 = 90.45 > 5
n(1-p) = 201*(1-0.45) = 201*0.55 = 110.55 > 5
Since both np and n(1-p) are greater than 5, the approximation can be used.
Item A and B are in decimal format, convert Item C to decimal by changing the fraction to a decimal by dividing 11 by 16:
11 / 16 = 0.6875
This makes Item C 3.6875
Now you have the 3 items as decimal format now put them in order from smallest to largest:
3.65, 3.6875, 4.1
Item A, Item C, Item B
D
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The gcf of 10 and 14 is 2.
Hope this helps!