The probability that the aircraft is overloaded is 97.98%, which means the pilot should take the action.
In a Normal distribution with mean ц and standard deviation σ, the z-score of a measure x is given by:
Z = X-ц / σ
· It measures how many standard deviations the measure is from the mean.
· After finding Z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
· By the Central Limit Theorem, the sampling distribution of sample means of the size n has standard deviation σ
σ = σ /
σ is standard deviation
n is the sample size.
Given that the mean and the standard deviation of the population is 176.1 lb and 35.4 respectively.
⇒ ц = 176.1 and σ = 35.4
For a sample of 43 passengers, we have
n = 43
σ = 
σ = 5.398
Z = X-ц / σ
Z = 
Z = -2.05 has p- value of 0.9798
The probability that the aircraft is loaded is
1 - p-value of Z
1 - 0.0202 = 0.9798
The probability that the aircraft is overloaded is 97.98%
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The answer is L = 59 + 2(d). If we plug in our numbers, we will get L = 59 + 2(32). 2*32 is 64, and if you add 59 you get 123 miles.
This isn’t apart of the question, but 59 would be the y-intercept. 2 miles per day (2/1) is the slope.
Answer:
z would be at (-6,6)
Step-by-step explanation:
hope that helps
Answer:
(D)
x + (x + 2) + (x + 4) = 66