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dexar [7]
3 years ago
7

What is the real distance from the youth center to the school?

Mathematics
2 answers:
GuDViN [60]3 years ago
5 0

Solution:

<u>We know that:</u>

  • Scale: 2 inches = 309 ft

Based on the map given, we can say that the <u>distance</u> between the youth center and the school is 6 inches.

<u>Use the scale to find out the real distance.</u>

  • 2 inches = 309 ft

<u>Divide 2 both sides:</u>

  • => 2/2 inches = 309/2 ft
  • => 1 inch = 309/2 ft

<u>Multiply 6 both sides:</u>

  • => 1 x 6 inch = 309/2 x 6 ft
  • => 6 inches = 309 x 3 ft
  • => 6 inches = 927 ft

The real distance is 927 ft.

ryzh [129]3 years ago
3 0
  • 2in=309ft
  • 1in=309/2=154.5ft

Distance in map=6in

  • Real distance=6(154.2)=927ft
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MAVERICK [17]

The number of students that were absent is; 24

<h3>How to find the Probability?</h3>

Let the total number of students be x .

The number of students which were absent = ¹/₃x.

Number of students which were present = ²/₃x

Thus;

Number of students who attended math's test = ¹/₂x

Number of students who attended physics test = ¹/₄x

No. of students who attended both tests = 6

A denotes number of students who attended math's test

B denotes number of students who attended physics test

Thus;

n(A) = ¹/₂x

n(B) = ¹/₄x

n(A ∩ B) = 6

n(A∪B) = number of students which were present

Thus;

n(A ∪ B) = n(A) + n(B) − n(A∩B)

²/₃x = ¹/₂x + ¹/₄x − 6

²/₃x = ³/₄x - 6

³/₄x - ²/₃x = 6

x = 72

Thus, number of students that were absent = ¹/₃ * 72

Number of students that were absent = 24

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