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Brilliant_brown [7]
2 years ago
13

Find side x, giving your answer to 1 decimal place. 81 7 cm 40° X​

Mathematics
1 answer:
worty [1.4K]2 years ago
6 0

Answer:

10.756 esa seria la respuesta

Step-by-step explanation:

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5th grade math. Correct answer will be marked brainliest.
Likurg_2 [28]

Answer: 1,285, 1,282, 1,278

Step-by-step explanation:

4 0
3 years ago
Given that curl F = 2yi – 2zj + 3k, find the surface integral of the normal component of curl F (not F) over (a) the open hemisp
Dimas [21]

Use Stokes' theorem for both parts, which equates the surface integral of the curl to the line integral along the surface's boundary.

a. The boundary of the hemisphere is the circle x^2+y^2=9 in the plane z=0, where the curl is \mathrm{curl}\vec F=2y\,\vec\imath+3\,\vec k. Green's theorem applies here, so that

\displaystyle\iint_S\mathrm{curl}\vec F\cdot\mathrm d\vec S=\int_{\partial S}\vec F\cdot\mathrm d\vec r=3\int_{x^2+y^2=9}\mathrm d\vec r

which means the value of the line integral is 3 times the area of the circle, or 27\pi.

b. The closed sphere has no boundary, so by Stokes' theorem the integral is 0.

7 0
3 years ago
How do you find x and y?
alexandr1967 [171]
Y=180-111=69
x=360-123-70-69=98
That's your answer.
7 0
3 years ago
The last 40 boat rentals at a boat rental company were 22 sunfish, 10 kayaks, and 8 rowboats.
Slav-nsk [51]
So whats the question my guy??
3 0
3 years ago
HELP A.S.A.P!!!! The data to represent average test scores for a class of 16 students includes an outlier value of 78. If the ou
kolezko [41]

When the outlier is removed The mean would increase.

<u>Step-by-step explanation:</u>

Outliers are the value that lies outside the set of data. i.e. the data doesn't fit in the group.

Removing outliers can affect mean more than median. Because outlier removal sometimes affect the median but in a small percentage or sometimes it will remain the same.

Let us prove, consider 16 values one with 78 and other 15 with values nearly 85, 84 that will give the mean value as 84.

78, 84, 82, 86, 84, 85, 83, 86, 82, 85, 84, 83, 86, 85, 86, 85.

Mean =\frac{Sum of the values}{Number of values}.

Mean =\frac{78+84+82+86+84+85+83+86+82+85+84+83+86+85+86+85}{16}.

Mean =\frac{1344}{16}.

Mean = 84.

Remove 78 from the data set then the data set is 84, 82, 86, 84, 85, 83, 86, 82, 85, 84, 83, 86, 85, 86, 85 and number of data is reduced to 15.

Mean =\frac{84+82+86+84+85+83+86+82+85+84+83+86+85+86+85}{15}.

Mean =\frac{1266}{15}.

Mean = 84.4.

The mean is increased.

8 0
3 years ago
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