Question

suppose the normal distribution has a mean of 98 and a standard deviation of 6. what is P(x < 92)? 0.16 0.025 0.84 0.975

Answer 1

Answer:

P(x < 92) is 0.16

Step-by-step explanation:

We are given that the normal distribution has a mean of 98 and a standard deviation of 6.

Mean =$\mu = 98$

Standard deviation = $\sigma = 6$

We are supposed to find  P(x < 92)

Formula : $Z=\frac{x-\mu}{\sigma}$

$Z=\frac{92-98}{6}$

Z=-1

Refer the z table for p value

So,p value = 0.1587

So, P(x < 92) is 0.16

Option A is true

Hence  P(x < 92) is 0.16