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jonny [76]
2 years ago
15

Liam ran 4 times around a circular track and did 100 jumping

Mathematics
2 answers:
zalisa [80]2 years ago
7 0

Answer:

the one complete circuit of the track is 600 meters

Step-by-step explanation:

divide the 2.4 kilometers by 4 which gives you your answer.

2.4 kilometers = 2,400 meters

2,400/4 = 600

Serggg [28]2 years ago
6 0

Answer:

600 m

Step-by-step explanation:

4 times around track = 2.4 km

2 times around track = 1.2 km

1 time around track = 0.6 km

0.6 km = 600 m

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What is the slope of a line through (-3, 4) and<br> (5, 6)?
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Answer:

slope= x2- x1/y2 -y1

= 5-(-3)/6-4

8/2= 4

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2 years ago
If Happie had ridden exactly 100 feet in 25
Strike441 [17]

Answer:

The speed rate is 100 feet per 25 seconds, or 20 feet every 5 seconds, (100 / 5 = 20)

Every minute is 60 seconds long, this means that to find out how fast she would roll in one minute we just need to do 60 / 5 = 12 and then do 12 x 20

12 x 20

10 x 20 = 200 feet per second

2 x 20 = 40 feet per second

200 + 40 = 240 feet per second

Happie would roll 240 feet in a minute at the speed of 100 feet per 25 seconds

Hope this helps!

6 0
3 years ago
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Find the surface area of a sphere with a radius of 30 m. leave your answer in terms of pi @Directrix
insens350 [35]
The formula for surface area of a sphere: A = 4 pi r^2.  
Since the radius is 30 m then A = 4pi30^2. 
 30^2 x 4 =3600
 A=3600pi m
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3 years ago
Read 2 more answers
500 increased by 30%
fgiga [73]

500 + 30% equals 650. 30% of 500 equals 150.

4 0
3 years ago
Help Please? GEOMETRY Use the word bank to help you with possible answers (there are extra options that are not to be used)
ipn [44]
Short Answers:

Answer for part A: Definition of perpendicular
Answer for part B: Right Angle Congruence Theorem
Answer for part C: Reflexive Property of Congruence
Answer for part D: Definition of Midpoint
Answer for part E: \triangle SXR \cong \triangle TXR
Answer for part F: CPCTC

-------------------------------------------------------------

Explanations:

Part A:

We are given that \overline{RX} \perp \overline{ST} which means, in english, "line segment RX is perpendicular to line segment ST"

By the very definition of perpendicular, this means that the two line segments form a right angle. This is visually shown as the red square angle marker for angle RXT. Angle RXS is also a right angle as well.

---------------------
Part B:

The Right Angle Congruence Theorem (aka Right Angle Theorem) is the idea that if we have two right angles, then we know that they are both 90 degrees so they must be congruent to one another. 

---------------------
Part C:

Any line segment is congruent to itself. This is because any line segment will have the same length as itself. It seems silly to even mention something so trivial but it helps establish what we need for the proof. 

---------------------
Part D:

We are given "X is the midpoint of segment ST" so by definition, X is in the very exact middle of ST. Midpoints cut segments exactly in half. SX is one half while TX is the other half. The two halves are congruent which is why SX = TX

---------------------
Part E:

Writing \triangle SXR \cong \triangle TXR means "triangle SXR is congruent to triangle TXR". These two triangles are the smaller triangles that form when you draw in segment RX

Side Note: SAS stands for "side angle side". The angle must be between the two sides. The pairing RX and RX forms one of the 'S' letters (see part C), while the pairing SX and TX forms the other 'S' (see part D). The angles between the sides are RXS and RXT (see part B). 

---------------------
Part F:

CPCTC stands for "Corresponding Parts of Congruent Triangles are Congruent"

It means that if we have two congruent triangles, then the corresponding parts are congruent. Back in part E, we proved the triangles congruent. For this part, we look at the pieces RS and RT (which correspond to one another; they are the hypotenuse of each triangle). They are proven congruent by CPCTC

If CPCTC is an odd concept to think about, then try thinking about something like this: you have two houses which are completely identical in every way. We can say that those two houses are congruent. If the houses are identical, then surely every piece that makes up the house is identical to its corresponding piece to the other house. For example, the front door to each house is both the same size, shape, color, made of the same material, designed in the same pattern, etc. So the two doors are congruent as well.
8 0
3 years ago
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