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Anit [1.1K]
4 years ago
8

Since 2005, the amount of money spent at restaurants in a certain country has increased at a rate of 8% each year, In 2005, abou

t $360 billion was spent at
restaurants. If the trend continues, about how much will be spent at restaurants in 2017?
​
Mathematics
1 answer:
Kryger [21]4 years ago
3 0

Answer:

This is an exponential growth problem.

 

The growth rate is 4% (0.04).

The time is 10 years (10 years from 2005 to 2015)

 

A = P(1+i)t

A = amount spent in 2015

P = amount spent in 2005

i = interest rate expressed as a decimal

t = # years

 

A = 500(1.04)10

A = 500(1.480244)

A = 740.122 ==> 740 billion

Step-by-step explanation:

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If s represents speed write an inequality to represent how fast a person can legally dive a vehicle in a school zone with a spee
ELEN [110]
The phrase “inequality” tells you that you will be using inequality signs, greater than, less than, greater than or equal to, or less than or equal to. Those signs look like this (not ordered) ≤ ≥ < >
So now we have to consider the speed limit 25mph, and remember s is used to represent how fast you are going. We can start be setting up 25_s and now we must determine what sign to use. Does it make sense to go faster than the speed limit? No it doesn’t, it’s a limit. what about equal to, does it make sense to go at the speed limit? Yes you can travel 25mph in a 25mph zone. So your speed will be less than or equal to 25, because you know you can’t go faster than that but you can travel at that number. So it looks like:
25 ≥ s.
If you need help understanding why I used that particular inequality sign message me for help.
5 0
3 years ago
Find the absolute maximum value for the function f(x) = x^2 − 4, on the interval [–3, 0) U (0, 2].
Andreyy89

Answer:

5

Step-by-step explanation:

The function y=x^2 -4 is

  • decreasing for all x\in [-3,0);
  • is increasing for all x\in (0,2]

(see attached diagram for details).

The maximum value of the function is at endpoints -3 or 2. find y(-3) and y(2):

y(-3)=(-3)^2-4=9-4=5\\ \\y(2)=4^2-4=0

So, the maximum value is 5.

5 0
3 years ago
25 points
igor_vitrenko [27]
Mona’s mom has baked 40 cookies.
4 0
3 years ago
Can someone help me with this one
melomori [17]

g(3) means that x is 3, and you just subsitute the x for 3. The solution is 34.

7 0
3 years ago
Use the Divergence Theorem to evaluate the following integral S F · N dS and find the outward flux of F through the surface of t
Xelga [282]

Answer:

Result;

\int\limits\int\limits_S { \textbf{F}} \, \cdot \textbf{N} d {S} = 32\pi

Step-by-step explanation:

Where:

F(x, y, z) = 2(x·i +y·j +z·k) and

S: z = 0, z = 4 -x² - y²

For the solid region between the paraboloid

z = 4 - x² - y²

div F        

For S: z = 0, z = 4 -x² - y²

We have the equation of a parabola

To verify the result for F(x, y, z) = 2(x·i +y·j +z·k)

We have for the surface S₁ the outward normal is N₁ = -k and the outward normal for surface S₂ is N₂ given by

N_2 = \frac{2x \textbf{i} +2y \textbf{j} + \textbf{k}}{\sqrt{4x^2+4y^2+1} }

Solving we have;

\int\limits\int\limits_S { \textbf{F}} \, \cdot \textbf{N} d {S} = \int\limits\int\limits_{S1} { \textbf{F}} \, \cdot \textbf{N}_1 d {S} + \int\limits\int\limits_{S2} { \textbf{F}} \, \cdot \textbf{N}_2 d {S}

Plugging the values for N₁ and N₂, we have

= \int\limits\int\limits_{S1} { \textbf{F}} \, \cdot \textbf{(-k)}d {S} + \int\limits\int\limits_{S2} { \textbf{F}} \, \cdot  \frac{2x \textbf{i} +2y \textbf{j} + \textbf{k}}{\sqrt{4x^2+4y^2+1} } d {S}

Where:

F(x, y, z) = 2(xi +yj +zk) we have

= -\int\limits\int\limits_{S1} 2z \ dA + \int\limits\int\limits_{S2} 4x^2+4y^2+2z \ dA

= -\int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 2z \ dA + \int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 4x^2+4y^2+2z \ dA

= \int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 4x^2+4y^2 \ dxdy

= \int\limits^2_{-2} \frac{(16y^2 +32)\sqrt{-(y^2-4)} }{3} dy

= 32π.

6 0
4 years ago
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