3 years ago

MathsWatch question:

Mathematics

1 answer:

Citrus2011 [14]3 years ago

7 0

Answer:

proving question

Step-by-step explanation:

The triangles have been drawn along with the circle and the figure is attached.

In ΔABD and ΔDCA

i) ∠ BAD = ∠ ADC = 90° [ Angle in a semicircle is always 90°]

ii) BD = AC [ both are diameters]

iii) AD = AD [ AD is a common side in both triangle]

Therefore, Δ ABD and ΔDCA are congruent to each other by RHS rule.

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