Question

MathsWatch question:

Answer 1

Answer:

proving question

Step-by-step explanation:

The triangles have been drawn along with the circle and the figure is attached.

In ΔABD and ΔDCA

i) ∠ BAD = ∠ ADC  = 90°  [ Angle in a semicircle is always 90°]

ii) BD = AC  [ both are diameters]

iii)  AD = AD [ AD is a common side in both triangle]

Therefore, Δ ABD and ΔDCA are congruent to each other by RHS rule.