I needa pass math q3
1 answer:
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You can solve this by using "similar triangles".
In triangle ABC, we are looking for side AC which is x. Side AC is similar to side DF in triangle EDF.
You can solve for side x by picking two sides in triangle ABC and their corresponding sides in triangle EDF. This is what I mean:
Substitute for the values of AC, BC, DF and EF:
To solve for y, do the same thing. Pick two sides on triangle ABC and their corresponding sides in triangle DEF.
Substitute for the values and solve:
We have the value x to be 5.5 units and y to be 6 units.
In triangle ABC, we are looking for side AC which is x. Side AC is similar to side DF in triangle EDF.
You can solve for side x by picking two sides in triangle ABC and their corresponding sides in triangle EDF. This is what I mean:
Substitute for the values of AC, BC, DF and EF:
To solve for y, do the same thing. Pick two sides on triangle ABC and their corresponding sides in triangle DEF.
Substitute for the values and solve:
We have the value x to be 5.5 units and y to be 6 units.
Answer:
Step-by-step explanation:
It's like solving any equation, except we have letters instead of numbers .
k = 3tm + rs {subtract rs from both sides}
k - rs = 3tm {divide both sides by (3m)}
{swap sides}
m≠0
{m must be ≠0 because you cannot divide by 0. There is no t for m=0}