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Gala2k [10]
2 years ago
13

Drag the numbers below to put them in order from least to greatest:

Mathematics
1 answer:
sesenic [268]2 years ago
4 0

Answer:

-0.5 , -0.85 , -0.87 , -0.9 , -0.9 , -1.2 , -1.67, -1.67

Step-by-step explanation:

you put the LEAST negative numbers frist, then you work your way up!

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There are five marbles in a bag two are yello and three are green. You draw a marble, replace it, and then draw another. What is
Sphinxa [80]

Answer: 2/5

Step-by-step explanation:

Since there are 5 marbles and 3 aren't yellow, you have a 2/5 chance to choose the other two yellow marbles

Hope this helps:)

5 0
2 years ago
Required information Skip to question NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to re
pogonyaev

The result for the given 14 length bit string is-

(a) The bit strings of length 14 which have exactly three 0s is 2184.

(b) The bit strings of length 14 which have same number of 0s as 1s is 17297280.

(c) The bit strings of length 14 which have at least three 1s is 4472832.

<h3>What is a bit strings?</h3>

A bit-string would be a binary digit sequence (bits). The size of the value is the amount of bits contained in the sequence.

A null string is a bit-string with no length.

The concept used here is permutation;

ⁿPₓ = n!/(n-x)!

Where, n is the total samples.

x is the selected samples.

(a) Because there are exactly three 0s, its other digits have always been one, hence the total of permutations is equal to;

n = 14 and x = 3 digits.

¹⁴P₃ = 14!/(14-3)!

¹⁴P₃ = 2184.

Thus, the bit strings of length 14 which have exactly three 0s is 2184.

(b) Because it is a bit string with 14 digits and it can only have digits 0 or 1, we must choose 7 0s and the remaining 7 1s, hence the number possible permutations is equal to;

n = 14 and x = 7 digits.

¹⁴P₇ = 14!/(14-7)!

¹⁴P₇ = 17297280.

Thus, the bit strings of length 14 which have same number of 0s as 1s is 17297280.

(c) The answer is identical to problem a, but the rest of a digits could be either 0 or 1, hence it must be doubled by 2¹¹ because there are 11 digits, each of which can be one of two options;

= 2184×2¹¹

= 4472832

Thus, he bit strings of length 14 which have at least three 1s is 4472832.

To know more about permutation, here

brainly.com/question/12468032

#SPJ4

The correct question is-

How many bit strings of length 14 have:

(a) Exactly three 0s?

(b) The same number of 0s as 1s?

(d) At least three 1s?

3 0
1 year ago
Samuel hughs sold $7,300 worth of merchandise at 12% commission. find the amount of commission
Sever21 [200]
So you are given the amount he sold which is $7300, and you are given his commission rate so all you have to do is this

7300 x 0.12 = 876

Therefore, his amount of commission is 876 dollars
4 0
3 years ago
Read 2 more answers
Find the volume of the rectangular prism
user100 [1]
Volume= Length • Width • Height

Given info: 6•8•9= 432cm cubed
8 0
3 years ago
Read 2 more answers
Rationalise 5 divide by square root of 12
Fantom [35]

Answer:

  (5√12)/12

Step-by-step explanation:

In general, 1/√a can be rationalized as (√a)/a. That is the denominator can be multiplied by the square root of the same number to rationalize it. The numerator needs to be multiplied by the same square root.

 \dfrac{5}{\sqrt{12}}=\dfrac{5}{\sqrt{12}}\cdot\dfrac{\sqrt{12}}{\sqrt{12}}=\boxed{\dfrac{5\sqrt{12}}{12}}

4 0
2 years ago
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