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Hoochie [10]
3 years ago
10

What makes this statement true? 7^-2

Mathematics
2 answers:
MaRussiya [10]3 years ago
7 0

For this case we have:

By definition, one of the properties of the power, known as negative integer power, states that:

a ^{-b}can be written as\frac{1}{a ^ b}

Thus,  7 ^{-2} can be written as \frac{1}{7 ^ 2} . So:

\frac{1}{7 ^ 2}= \frac{1}{(7 * 7)}=\frac{1}{49}

Answer:

Power of negative integer exponent:

7^{-2} =\frac{1}{7 ^ 2}= \frac{1}{(7 * 7)}=\frac{1}{49}


Alexxx [7]3 years ago
4 0
The negative power means 1/the number to the given power

This means that 7^-2 can be rewritten as 1/(7^2)
7^2 = 7*7
Therefore:
1/(7^2) = 1/(7*7)
7*7 = 49
Therefore:
1/(7*7) = 1/49

Based on the above calculations:
7^-2 is equal to 1/49
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Step-by-step explanation:

Answer:

0.430625 = 0.431

Step-by-step explanation:

Let W represent winning, D represent a draw and L represent a loss.

12+ points can be garnered in each of the following ways.

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The probability of getting 12+ points is the sum of all these 7 probabilities.

Knowing that P(W) = 0.5

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P(5W 0D 1L) = [6!/(5!0!1!)] 0.5⁵ 0.1⁰ 0.4¹ = 0.075

P(4W 2D 0L) = [6!/(4!2!0!)] 0.5⁴ 0.1² 0.4⁰ = 0.09375

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P(3W 3D 0L) = [6!/(3!3!0!)] 0.5³ 0.1³ 0.4⁰ = 0.0025

The probability of getting 12+ points = 0.015625 + 0.01875 + 0.075 + 0.09375 + 0.075 + 0.15 + 0.0025 = 0.430625

Read more on Brainly.com - brainly.com/question/14850440#readmore

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